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3 years ago

Examples of drawing packages

Physics

1 answer:

Marat540 [252]3 years ago

5 0

Answer:

The answer are given above in attachment.

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Find the distance in nm between two slits that produces the first minimum for 410-nm violet light at an angle of 14.5°.

Galina-37 [17]

Answer:

820 nm

Explanation:

We are given that

Wavelength= $\lambda=410 nm$

$\lambda=410\times 10^{-9} m$

$1nm=10^{-9} m$

$\theta=14.5^{\circ}$

For first minimum therefore

m=0

We know that for destructive interference

$(m+\frac{1}{2})\lambda=dsin\theta$

Substitute the values

$(0+\frac{1}{2})\times 410\times 10^{-9}=dsin 14.5$

$d=\frac{410\times 10^{-9}}{2\times sin 14.5}$

$d=820\times 10^{-9} m=820 nm$

Hence, the distance between two slits that produces the first minimum=820 nm

5 0

2 years ago

Read 2 more answers

24. Most cleaning solutions like soap, with a pH of 8-9 are examples of a(n)

Sphinxa [80]

24. A, natural ph scale for it not to be acidic is 7-8

25. A, not sure about this one

26. A, looked it up

27. A, because it has to be shaken up to make the mixture appear and taste more combined.

28. D, i just guessed

29. D, that answer is stupid so it is the answer because it said not a property

30. A, looked it up

8 0

3 years ago

A 50kg car is moving at a velocity of 4 m/s. After a collision, the car is moving at a velocity of 5m/s.

earnstyle [38]

Answer:

Explanation:

The equation for momentum is p = mv; therefore,

p1 = 50(4) so

p1 = 200

p2 = 50(5) so

p2 = 250

The impulse, the change in the momentum, is 50, going in the same direction.

8 0

2 years ago

In the waves lab, you changed ____ to see how it would affect wave speed.

ikadub [295]

Hi there!

I believe the answer is transversal or transverse.

6 0

3 years ago

In an electrical circuit 200mC of charge flows through a 50kohm resistor in 90 seconds. What is the power

ss7ja [257]

Answer: $0.2464\ W$

Explanation:

Given

Charge $Q=200\ mC$

Resistance $R=50\ k\Omega$

Time $t=90\ s$

Charge is the amount of current flown in a particular time

$Q=It\\\Rightarrow 200\times 10^{-3}=I\times 90\\\\\Rightarrow I=\dfrac{200\times 10^{-3}}{90}\\\\\Rightarrow I=2.22\times 10^{-3}\ A$

Power is the given by $P=I^2R$

Insert values

$\Rightarrow P=\left(2.22\times 10^{-3}\right)^2\times 50\times 10^3\\\\\Rightarrow P=246.42\times 10^{-3}\ W\\\\\Rightarrow P=0.2464\ W$

The power is in the circuit is $0.2464\ W$ .

8 0

2 years ago