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2 years ago

Someone plssss help meeee !!!! How much energy is required to vaporize 112 g of water? ???

Chemistry

1 answer:

asambeis [7]2 years ago

3 0

Answer:

6.05 × 10⁴ cal

Explanation:

Step 1: Given and required data

Mass of water (m): 112 g

Enthalpy of vaporization of water (ΔHvap): 540 cal/g

Step 2: Calculate how much energy is required to vaporize 112 g of water

Vaporization is a physical change in which a substance goes from the liquid state to the gaseous state. We can calculate the energy required (Q) using the following expression.

Q = ΔHvap × m

Q = 540 cal/g × 112 g = 6.05 × 10⁴ cal

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