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erastovalidia [21]
4 years ago
9

The two particles are both moving to the right. Particle 1 catches up with particle 2 and collides with it. The particles stick

together and continue on with velocity vf. Which of these statements is true?
A. vf=v1
B. vf=v2
C. vf is less than v2
D. vf is less than v2 but greater than v1
E. vf>v1

Physics
1 answer:
Irina18 [472]4 years ago
8 0

Answer:

See bolded below.

Explanation:

Consider the " Before " and " After. " " Before, " this particle 1 was trying to catch up with this particle 2, and " after " particle one had collided with particle two. Take a look at the attachment below for a more detailed examination.

Here is how this will play out. Particle 1, with great velocity, will hit particle 2, which would mean that Particle 2 has less velocity than Particle 1. Now after the collision, energy is transferred to Particle 2, and while Particle 1 has now stopped in it's tracks, Particle 2 - with more energy than before - will continue as long as it has to before friction eventually brings it to a stop.

_______________________________________________________

From this we can conclude that Vf, from the picture below, must have less energy than V1, but more energy than V2 - and vice versa.

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45. An object with a mass of 25 kg accelerates east at a rate of 7 m/s? What fiet force is acting on the object?
ZanzabumX [31]

Answer:

According to newton's second law of motion F=ma so

Explanation:

Data:-M=25kg ,a=7m/s² F=? ,solution:-F=ma ,F=25×7=175kgm/s² or N

6 0
4 years ago
Drag each tile to the correct box. Arrange the steps in order to describe what happens to a gas when it cools. The particles of
vredina [299]

Answer:

Ok, as the gas starts to cool down, the kinetic energy of the particles starts to decrease, so the first thing that happens is:

"the gas loses thermal energy" (as the gas cools down, the temperature decreases, so it loses thermal energy)

Now, the kinetic energy must decrease, so now:

"the particles of gas move slower".

Then, as the particles start to move slower, they start to get closer to eachother, then we have:

"The space between the gas particles decreases."

As the particles start to get close to eachother, the density of the gas starts to increase, until a point where we get to the condensation point, here we have a change of phase and the gas changes to a liquid, so here we have:

"The gas changes to a liquid."

4 0
3 years ago
A supply plane needs to drop a package of food to scientists working on a glacier in greenland. the plane flies 100 m above the
pishuonlain [190]

The package should be dropped <u>678 m</u> short of the target.

A package dropped from a plane which is moving at a speed v, has a horizontal velocity equal to the horizontal velocity of the plane. It has a parabolic trajectory, traversing a horizontal range x while it falls through a vertical height y.

The package has no initial vertical velocity, and it falls through a height y under the action of the acceleration due to gravity g.

Use the equation,

y=\frac{1}{2} gt^2

Write an expression for t, the time taken for the package to fall through y.

t^2=\frac{2y}{g}

Substitute 100 m for y and 9.81m/s² for g.

t^2=\frac{2y}{g}\\ =\frac{2(100m)}{9.81m/s^2} \\ =20.39s^2\\ t=4.52s

In the time t  the package travels a horizontal distance x. The horizontal velocity of the package remains constant, since no force acts along the horizontal direction.

Therefore, the horizontal distance traveled by the package is given by,

x=vt\\ =(150m/s)(4.52s)\\ =678m

If the package is released <u>678m</u> before the target, the package would reach the scientists working in Greenland.

6 0
4 years ago
Two spaceships are observed from earth to be approaching each other along a straight line. Ship A moves at 0.40c relative to the
nirvana33 [79]

Answer:

0.80 c

Explanation:

The computation of speed is shown below:-

Here, The speed of the captain ship A report for speed of the ship B which is

S = \frac{S_A + S_B}{1 + \frac{(S_AS_B)}{c^2} }

where

S_A indicates the speed of the ship A

S_B indicates the speed of the ship B

and

C indicates the velocity of life

now we will Substitute 0.40c for A and 0.60 for B in the equation which is

S = \frac{0.40c + 0.60c}{1 + \frac{(0.40c)(0.60c)}{c^2} }

after solving the above equation we will get

0.80 c

So, The correct answer is 0.80c

5 0
3 years ago
A Chinook salmon can jump out of water with a speed of 6.70 m/s6.70 m/s . How far horizontally dd can a Chinook salmon travel th
aksik [14]

Answer:

R = 3.88 m

Explanation:

As the Chinook salmon leaves the water till it gets back into the water it is performing a projectile motion with the following parameters:

V₀ = Launch Speed = 6.7 m/s

θ = Launch Angle = 29°

R= Range of Projectile= Horizontal Distance Covered by Chinook salmon= ?

The value of the range of a projectile is given by the following formula:

R = (V₀² Sin 2θ)/g

R = [(6.7 m/s)² Sin {(2)(29°)}/(9.8 m/s²)]

R = [(6.7 m/s)² Sin (58°)/(9.8 m/s²)]

<u>R = 3.88 m</u>

8 0
4 years ago
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