Answer:
Explanation:
Bone has a Young’s modulus of about
1.8 × 1010 Pa . Under compression, it can
withstand a stress of about 1.66 × 108 Pa before breaking.
Assume that a femur (thigh bone) is 0.56 m
long, and calculate the amount of compression
this bone can withstand before breakin :).
The offspring would genetically identical to the parents because regeneration is a form of asexual reproduction.
Uh it’s D i’m pretty sure
Answer:
Explanation:
<u>Horizontal Launch
</u>
It happens when an object is launched with an angle of zero respect to the horizontal reference. It's characteristics are:
- The horizontal speed is constant and equal to the initial speed
- The vertical speed is zero at launch time, but increases as the object starts to fall
- The height of the object gradually decreases until it hits the ground
- The horizontal distance where the object lands is called the range
We have the following formulas
Where is the initial horizontal speed, is the vertical speed, t is the time, g is the acceleration of gravity, x is the horizontal distance, and y is the height.
If we know the initial height of the object, we can compute the time it takes to hit the ground by using
Rearranging and solving for t
We then replace this value in
To get
The initial speed depends on the initial height y=32.5 m, the range x=107.6 m and g=9.8 m/s^2. Computing
The launch velocity is
Answer:
B = 1.1413 10⁻² T
Explanation:
We use energy concepts to calculate the proton velocity
starting point. When entering the electric field
Em₀ = U = q V
final point. Right out of the electric field
em_f = K = ½ m v²
energy is conserved
Em₀ = Em_f
q V = ½ m v²
v =
we calculate
v =
v =
v = 25.15 10⁴ m / s
now enters the region with magnetic field, so it is subjected to a magnetic force
F = m a
the force is
F = q v x B
as the velocity is perpendicular to the magnetic field
F = q v B
acceleration is centripetal
a = v² / r
we substitute
qvB =1/2 m v² / r
B = v
we calculate
B =
B = 1.1413 10⁻² T