Answer:
1.563 moles of SO3.
Explanation:
We begin by calculating the number of mole present in 100g of sulphur dioxide, SO2. This can be obtained as follow:
Molar mass of SO2 = 32 + (16x2) = 64g/mol
Mass of SO2 = 100g
Mole of SO2 =..?
Mole = mass/Molar mass
Mole of SO2 = 100/64
Mole of SO2 = 1.563 mole
Now, we can obtain the number of mole of sulphur trioxide, SO3 produce from the reaction as follow:
2SO2 + O2 —> 2SO3
From the balanced equation above,
2 moles of SO2 reacted to produce 2 moles of SO3.
Therefore, 1.563 moles of SO2 will also react to produce 1.563 moles of SO3.
Therefore, 1.563 moles of SO3 is obtained from the reaction.
