Answer:
The aqueous solution of 
therefore would be "strongly basic."
Explanation:
Strongly basic because the is completely an ionic compound. These compound can be 100% splitted into metal ions and hydroxide ion when used in the aqueous solution. Each moles dissolves which can give rise to mole of hydrogen ions when used in the solution. Whereas strong bases are not soluble in water as well. in the presence of water equilibrium can also be achieved. A strong base has the capability which can just remove the proton from the molecule.
First, write the equation:
Cu + O2 -> CuO
Now, balance:
2 Cu + O2 -> 2 CuO
The diameter of the pool is 4
Explanation:
To calculate the diameter we must write the values given in the question, here
The circumference of the pool is given as C=12.56 feet.
To calculate the diameter of the pool,
If radius is given, Multiply the radius by 2
If Circumference is given divide the circumference by Pi (π)
the constant value for Pi (π)=3.14
Diameter(D)= C/π
12.56/3.14
=4
The diameter for the plastic wading pool is 4
Answer:
5. gains two electrons.
Explanation:
In order to determine the most stable monoatomic ion of oxygen, we need to consider the octet rule: atoms will gain, lose or share electrons to complete their valence shell with 8 electrons.
Oxygen is in the Group 16 in the Periodic Table, so it has 6 valence electrons. Therefore, it will gain two electrons to have the electron configuration of the closest noble gas.
pH of 0.048 M HClO is 4.35.
<u>Explanation:</u>
HClO is a weak acid and it is dissociated as,
HClO ⇄ H⁺ + ClO⁻
We can write the equilibrium expression as,
Ka = ![$\frac{[H^{+}] [ClO^{-}] }{[HClO]}](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%20%5BClO%5E%7B-%7D%5D%20%20%7D%7B%5BHClO%5D%7D)
Ka = 4.0 × 10⁻⁸ M
4.0 × 10⁻⁸ M = 
Now we can find x by rewriting the equation as,
x² = 4.0 × 10⁻⁸ × 0.048
= 1.92 × 10⁻⁹
Taking sqrt on both sides, we will get,
x = [H⁺] = 4.38 × 10⁻⁵
pH = -log₁₀[H⁺]
= - log₁₀[ 4.38 × 10⁻⁵]
= 4.35
