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Mars2501 [29]
2 years ago
6

Balance the following chemical equation: Mg(OH)₂ ​+ HCI → MgCI₂ ​+ H₂ ​O

Chemistry
1 answer:
geniusboy [140]2 years ago
6 0

Answer:

Mg(OH)₂ ​+  2HCI → MgCI₂ ​+ 2 H₂ ​O

Explanation:

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The heat of fusion for a substance is 122 joules per gram. How many joules of heat are need to melt 7.50 grams of this substance
daser333 [38]
<h3>Answer:</h3>

915 Joules

<h3>Explanation:</h3>
  • The heat of fusion is the heat that is required to convert a given mass of a substance from solid state to liquid state without change in temperature.
  • In this case, we are given specific heat of a substance as 122 joules per gram
  • It means that amount of heat equivalent to 122 joules is required to change 1 gram of the substance from solid state to liquid state.
  • Therefore, we can determine the amount of heat needed to change 7.5 grams of the substance from solid to liquid state.

1 g = 122 Joules

7.5 g = ?

       = 122 × 7.5

      = 915 Joules

Thus, 7.5 g of the substance at its melting point will require 915 Joules of heat to melt.

4 0
3 years ago
________________ is a synthetic polymer classified as plastics.
Igoryamba

Answer: Polythene

Polythene is a synthetic polymer classified as plastics.

Explanation:

Polythene is formed artificially from several repeating units of ethene molecules (monomers) in a reaction known as polymerization.

The polyethene can be represented as [CH2-CH2]n, where n is thousands to ten thousands unit of ethene.

It is used to make

- plastic bags,

- cable insulators

- plastic crates etc

Thus, polythene is a synthetic polymer of ethene, and classified as plastics.

8 0
3 years ago
Read 2 more answers
How does 0.5 m sucrose (molecular mass 342) solution compare to 0.5 m glucose (molecular mass 180) solution?
mash [69]

Answer : Both solutions contain 3.011 X 10^{23} molecules.

Explanation : The number of molecules of 0.5 M of sucrose is equal to the number of molecules in 0.5 M of glucose. Both solutions contain 3.011 x 10^{23} molecules.

Avogadro's Number is  N_{A} =  6.022 X 10^{23} which represents particles per mole and particles may be typically molecules, atoms, ions, electrons, etc.

Here, only molarity values are given; where molarity is a measurement of concentration in terms of moles of the solute per liter of solvent.

Since each substance has the same concentration, 0.5 M, each will have the same number of molecules present per liter of solution.

Addition of molar mass for individual substance is not needed. As if both are considered in 1 Liter they would have same moles which is 0.5.

We can calculate the number of molecules for each;

Number of molecules  = N_{A} X M;

∴  Number of molecules =  6.022 X 10^{23} X 0.5 mol/L X 1 L which will be  = 3.011 X 10^{23}

Thus, these solutions compare to each other in that they have not only the same concentration, but they will have the same number of solvated sugar molecules. But the mass of glucose dissolved will be less than the mass of sucrose.

7 0
2 years ago
Read 2 more answers
Imperial shrimp attach themselves to sea cucumbers for transportation. The interaction saves energy and improves food availabili
Sveta_85 [38]

Answer:

a

Explanation:

commensalism

4 0
3 years ago
Calculate Ho298 for the process
Inga [223]

Explanation:

As per the Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

Hence, according to this law the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Sb + \frac{3}{2}Cl_2 \rightarrow SbCl_{3}    \Delta H^0_1 =  -314 kJ  ..........(1)

SbCl_{3} + Cl_2 \rightarrow SbCl_{5}    \Delta H^0_2 = -80kJ   ..............(2)

The final reaction is as follows:  

Sb + \frac{5}{2}Cl_{2} \rightarrow SbCl_{5}  \Delta H^0_3 = ?  .............(3)

Therefore, adding (1) and (2) we get the final equation (3) and value of \Delta H^{0}_{3} at 298 K will be as follows.

             \Delta H^{0}_{3} = \Delta H^{0}_{1} + \Delta H^{0}_{2}    

                       = -314 kJ + (-80) kJ

                       = -394 kJ

Thus, we can conclude that H^{o} at 298 K for the given process is -394 kJ.

4 0
3 years ago
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