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Nina [5.8K]
3 years ago
5

C. How many moles of gas are in a container with a volume of 9.55 mL at 35 °C and a pressure of 895 mmHg?

Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
5 0

Answer: There are 4.45\times 10^{-4}moles of gas are in a container with a volume of 9.55 mL at 35 °C and a pressure of 895 mmHg

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 895 mm Hg= 1.18 atm  (760 mm Hg= 1 atm)

V = Volume of gas = 9.55 ml = 0.00955 L   (1 L=1000ml)

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =35^0C=(35+273)K=308K

n=\frac{PV}{RT}

n=\frac{1.18atm\times 0.00955L}{0.0821L atm/K mol\times 308K}=4.46\times 10^{-4}moles

Thus there are 4.45\times 10^{-4}moles of gas are in a container with a volume of 9.55 mL at 35 °C and a pressure of 895 mmHg

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<h3>What is a Percent yield</h3>

A percent yield of a substance measures the amount of the substance actually obtained as a percentage ratio of expected yield.

Percent yield = actual yield / expected yield × 100%

<h3>How to calculate the mass of aluminium obtained from bauxite </h3>

From the data given:

40 % of the bauxite is converted to aluminium oxide.

Volume of bauxite = 1 m^3

40 % of 1 m^3 = 0.4 m^3

volume of aluminium oxide = 0.4 m^3

density of aluminium oxide = 3965 kg/m^3

  • Using mass = density × volume

mass of aluminium oxide = 0.4 × 3965 kg

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molar mass of aluminium oxide = 102 g

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Therefore, mass of aluminium obtained from 1 m^3 of bauxite is 419810 g

Learn more about percent yield at: brainly.com/question/8638404

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