Answer:
The acceleration is about 9.8 m/s2 (down) when the ball is falling.
Explanation:
The ball at maximum height has velocity zero
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.8 m/s² (positive downward and negative upward)
The accleration 9.8 m/s² will always be acting on the body in opposite direction when the body is going up and in the same direction when the body is going down. The acceleration on the body will never be zero
Answer:
80 ft/s
Explanation:
Use III equation of motion
V^2 = U^2 + 2g h
Here, U = 0, g = 32 ft/s^2, h = 100 ft
V^2 = 0 + 2 × 32 ×100
V^2 = 6400
V = 80 ft/s
Answer:
v = 18.84 m/s
Explanation:
Given that,
The length of the string, r = 1.5 m (it will act as radius)
The rubber stopper makes 120 complete circles every minute.
Since, 1 minute = 60 seconds
It means, its frequency is 2 circles every second.
Let we need to find the average speed of the rubber stopper. It can be calculated as follows :
d is distance, 
and 1/T = f (frequency)
So, the average speed of the rubber stopper is 18.84 m/s.
Answer:
Lol, you should do Nate, Bobby, Cindy, Joe, and Beth
Jk, if you want to be series and probably not fail go for these:
If it wants types of small/average stars, then go with
Small star names:
OGLE-TR-122B
Gliese 229 B
TRAPPIST-1
Teegarden's Star
Luyten 726-8 (A and B)
Proxima Centauri
Wolf 359 111400
Ross 248
Barnard's Star
CM Draconis B
Ross 154 167000
CM Draconis A
Kapteyn's Star
I am going to say
C. Energy contained in the nucleus of an atom
