An m = 7.25 kg mass is suspended on a string which is pulled upward by a force of F = 76.7 N as shown in the figure. If the upwa
rd velocity of the mass is 2.25 m/s right now, then what is the velocity 3.50 s later?
1 answer:
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Answer:
V₁ = 1.75 m³
Explanation:
Assuming the gas to be an ideal gas. At constant temperature, the relationship between the volume and temperature of an ideal gas is given by Boyle's Law as follows:
where,
P₁ = Initial Pressure of the Gas = 4 KPa
V₁ = Initial Volume of the Gas = ?
P₂ = Final Pressure of the Gas = 2 KPa
V₂ = Final Volume of the Gas = 3.5 m³
Therefore,
<u>V₁ = 1.75 m³</u>