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NARA [144]
3 years ago
11

12. your friend with great excitement tells you about his newest idea to solve the energy crisis: he wants to use an electromoto

r to drive a generator and then use part of the electric power generated to power the electromotor while using the rest to power his home. what would you tell him?
Physics
2 answers:
mixas84 [53]3 years ago
4 0
I would tell him, in the kindest, most gentle way I could manage,
to fahgeddaboudit. 

The total amount of energy doesn't change.  Energy is never created,
and it never disappears.  If you have some energy, then it had to come
from somewhere, and if you used some energy, then it had to go
somewhere. 

You can never get more energy out of the electromotor than you put into it,
 and in the real world, you can't even get THAT much out, because some
of it is always used on the way through.

Pour yourself a cold glass of soda, then look up "Perpetual Motion" or
"Free Energy" on the internet, relax, and enjoy the show.  They are all
fakes.  They may not all be intentionally meant to fool you, but they are
all impossible.
Semenov [28]3 years ago
3 0

Explanation:

My friend's new idea about solving the energy crisis will not be successful as we cannot create energy out of nowhere and destroy it. Energy can only be transferred into some other form of energy. This is also called the "perpetual motion machine of the first kind" which is not possible according to the 1st law of thermodynamics. Also his idea to drive the generator with the electromotor and then power both the electromotor and rest power his house is also impossible the electromotor has to reject some of the energy to the universe in terms of heat or sound. Again this violates the 2nd law of thermodynamics which states that any machine cannot transfer all the energy to perform work without rejecting any. This is the "perpetual motion machine of the second type" which is also not possible.

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A 100-kg tackler moving at a speed of 2.6 m/s meets head-on (and holds on to) an 92-kg halfback moving at a speed of 5.0 m/s. Pa
DIA [1.3K]

Given that,

Mass of trackler, m₁ = 100 kg

Speed of trackler, u₁ = 2.6 m/s

Mass of halfback, m₂ = 92 kg

Speed of halfback, u₂ = -5 m/s (direction is opposite)

To find,

Mutual speed immediately after the collision.

Solution,

The momentum of the system remains conserved in this case. Let v is the mutual speed after the collision. Using conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{100\times 2.6+92\times (-5)}{(100+92)}\\\\V=-1.04\ m/s

So, the mutual speed immediately after the collision is 1.04 m/s but in opposite direction.

3 0
3 years ago
If a particle with a charge of +4.3 × 10−18 C is attracted to another particle by a force of 6.5 × 10−8 N, what is the magnitude
AveGali [126]

Answer: 1.5×10^10 N/C

Explanation:

E= F/q

Where E= magnitude of the electric field

F= force of attraction

q= charge of the given body

Given F= 6.5×10^-8 N

q= 4.3× 10^-18 C

Therefore, E = 6.5×10 ^-8/ 4.3×10^-18

E = 1.5×10^10 N/C

7 0
3 years ago
An artist working on a piece of metal in his forging studio plunges the hot metal into oil in order to harden it. The metal piec
lutik1710 [3]

Answer:

The temperature of the metal is  T_m  =  376.8 ^o C

Explanation:

From the question we are told that

     The mass of the metal is  M =  60 \ kg

     The specific heat of the metal is  c_p  =  0.1027 kcal/(kg \cdot ^oC)

       The mass of the oil is M_o  =  810 \ kg

       The temperature of the oil is  T_o  =  35^oC

       The specific heat of oil is  c_o  =  0.7167 kcal/(kg \cdot ^oC )

       The equilibrium temperature is T_e  =  39 ^oC

According to the law of energy conservation

     Heat lost by metal  =  heat gained by the oil

So  

   The quantity  of heat lost by the metal is mathematically represented as

               Q =  - Mc_p \Delta T

=>            Q =  -Mc_p (T_m  -  T_c)

Where T_ m  the temperature of metal before immersion

The negative sign show heat lost

The quantity  of gained t by the metal is mathematically represented as      

           Q =  M_o c_o \Delta T

=>        Q =  M_o c_o (T_c - T_o)

So  

         Mc_p (T_m  -  T_c)   =   M_o c_o (T_c - T_o)

substituting values

          - 60 * 0.1027 (T_m  - 39)   =   810 * 0.7167 *  (39 - 35)

=>       T_m  =  376.8 ^o C

         

6 0
3 years ago
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