Answer:
31.1 N
Explanation:
m = mass attached to string = 0.50 kg
r = radius of the vertical circle = 2.0 m
v = speed of the mass at the highest point = 12 m/s
T = force of the string on the mass attached.
At the highest point, force equation is given as
Inserting the values
T = 31.1 N
Answer:
Impulse is 1.239 kg.m/s in upward direction
Explanation:
Taking upward motion as positive and downward motion as negative.
Downward motion:
Given:
Mass of ball (m) = 0.150 kg
Displacement of ball (S) = -1.25 m
Initial velocity (u) = 0 m/s
Acceleration is due to gravity (g) = -9.8 m/s²
Using equation of motion, we have:
Since, the motion is downward, final velocity must be negative. So,
Upward motion:
Given:
Displacement of ball (S) = 0.665 m
Initial velocity () = 4.95 m/s(Upward direction)
Acceleration is due to gravity (g) = -9.8 m/s²
Using equation of motion, we have:
Since, the motion is upward, final velocity must be positive. So,
Now, impulse is equal to change in momentum. So,
Impulse = Final momentum - Initial momentum
Therefore, the impulse given to the ball by the floor is 1.239 kg.m/s in upward direction.