Question

In Canada and the United Kingdom, devices that measure blood glucose levels provider reading to millimoles per litre. If

Answer 1

Answer:

The concentration of glucose 95.4 mg/dL:

Explanation:

$Molarity = 1000 \times \text{milliMolarity}$

Concentration of glucose in blood = 5.3 milli Molar

This means that 5.3 milli moles are present in 1 l of solution.

5.3 milli moles = 0.0053 moles

So, from this we can say that  0.0053 moles of glucose are present in 1 L solution.

Mass of 0.0053 moles of glucose :

= 0.0053 mol × 180 g/mol = 0.954 g

(1 g = 1000 mg)

0.954 g = 954 mg

945 milli grams in 1 liter of the solution.

(1 L = 10 dL)

The concentration of glucose in mg/dL:

$\frac{945 mg}{10 dL}=94.5 mg/dL$