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Kipish [7]
3 years ago
14

The wire and battery did not light the lightbulb inthe diagram. Please explain why. Use the Terms Bulb, Battery, Negitive charge

and wire in your explination
Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
7 0
The lightbulb is connectd to the positive charge side of the battery, but the wire
 is not connected to the negative charge side
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Is a mixture of toys a substance or homogeneous and heterogeneous mixture
Aleonysh [2.5K]

Answer:

homogeneous

Explanation:

one type of molecules

6 0
3 years ago
___ Particles of which of the following have the greatest thermal energy
abruzzese [7]
Salutations!

<span>___ Particles of which of the following have the greatest thermal energy

Gas is the particle that has the greatest thermal energy. Gas has the greatest thermal energy because the movement between particles is clump. This thermal energy is then converted into kinetic energy.

Thus, your answer is option C.

Hope I helped (:

Have a great day!</span>
5 0
3 years ago
_NaHCO(s) --&gt; _CO2+_NaCO(s)+_H2O<br><br>balance the equation​
elena55 [62]

The balanced equation :

2NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

<h3>Further explanation</h3>

Given

Reaction

NaHCO(s) --> _CO2+_NaCO(s)+_H2O

Required

The balanced equation

Solution

Maybe the equation should be like this :

NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

Give a coefficient

NaHCO₃⇒aCO₂ + bNa₂CO₃+cH₂O

Make an equation

Na, left=1, right=2b⇒2b=1⇒b=1/2

H, left=1, right=2c⇒2c=1⇒c=1/2

C, left=1, right=a+b⇒a+b=1⇒a+1/2=1⇒a=1/2

The equation becomes :

NaHCO₃⇒1/2CO₂ +1/2Na₂CO₃+1/2H₂O x2

2NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

5 0
3 years ago
If an experiment with 10.2 g barium chloride produced 14.5 g silver chloride, calculate thr experimental mole ratio of silver ch
Leni [432]
The  experimental  mole ratio  of silver chloride  to  barium chloride  is calculated as below

fin the mole of each compound

mole= mass/molar  mass
moles of AgCl = 14.5g/142.5 g/mol = 0.102  moles of AgCl
moles of BaCl2 = 10.2 g/208 g/mol =  0.049  moles of BaCl2

find the  mole ratio  by dividing each mole with the smallest  mole(0.049)

AgCl= 0.102/0.049 =2
BaCl2 = 0.049/0.049 =1
therefore  the mole   ratio   AgCl to  BaCl2  is  2 :1
3 0
3 years ago
Read 2 more answers
An interpenetrating primitive cubic structure like that of CsCl with anions in the corners has an edge length of 664 pm. If the
san4es73 [151]

Answer:

the ionic radius of the anion r^- = 312.52 \ pm

Explanation:

From the diagram shown below :

The anion Cl^- is located at the corners

The cation Cs^+ is located at the body center

The Body diagonal length =  \sqrt{3 \ a }

∴ 2 \ r^+ \ + 2r^- \ = \sqrt{3 \ a}  \\ \\ r^+ +r^- = \frac{\sqrt{3}}{2} a

Given that :

\frac{r^+}{r^-} =0.84   (i.e the  ratio of the ionic radius of the cation to the ionic radius of

                 the anion )

0.84r^- \ + r^- \ = \frac{\sqrt{3}}{2}a  \\ \\  1.84 r^- = \frac{3}{2}a \\ \\ r^- = \frac{\sqrt{3}}{2*1.84}a

Also ; a =  664 pm

Then :

r^- = \frac{\sqrt{3} }{2*1.84}*664 \ pm\\ \\ r^- = 312.52 \ pm

Therefore,  the ionic radius of the anion r^- = 312.52 \ pm

4 0
3 years ago
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