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Kipish [7]
3 years ago
14

The wire and battery did not light the lightbulb inthe diagram. Please explain why. Use the Terms Bulb, Battery, Negitive charge

and wire in your explination
Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
7 0
The lightbulb is connectd to the positive charge side of the battery, but the wire
 is not connected to the negative charge side
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Vote you brainiest please help me
Nezavi [6.7K]

Okay happy to help<3

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8 0
3 years ago
How do different stimuli affect the survival behavior of an organism?
Vlad [161]
Organisms change their behavior in responses to changes in the environment.

All living things can respond to stimuli in the exterior environment, it is a form of energy-light waves or sound vibrations, From what they sense they will make necessary changes to their diet and or where they are located. Such as winter weather which is a type stimuli will cause some animals to start talking.
6 0
3 years ago
Had beryllium and calcium already been discovered
Lina20 [59]

Answer:

Yes

Beryllium is a chemical element with the symbol Be and atomic number 4. It is a steel-gray, strong, lightweight and brittle alkaline earth metal. ... Notable gemstones high in beryllium include beryl (aquamarine, emerald) and chrysoberyl.

Calcium is a mineral that is necessary for life. In addition to building bones and keeping them healthy, calcium enables our blood to clot, our muscles to contract, and our heart to beat. About 99% of the calcium in our bodies is in our bones and teeth.

3 0
3 years ago
What is the mass of a cube measuring 3cm on each side that had a density of 8.1g/cm3?
Hunter-Best [27]

Answer:

48.6 g

Explanation:

Given data:

Length of one side = 3 cm

Density of cube = 8.1 g/cm³

Mass of cube = ?

Solution:

First of all we will calculate the volume of cube.

V = length × height × width

V = 3 cm × 3cm× 3cm

V = 27cm³

Now we will determine the mass by using density formula.

d = m/v

d = density

m = mass

v = volume

8.1 g/cm³ = m/ 27 cm³

m = 8.1 g/cm³ ×27 cm³

m = 48.6 g

6 0
3 years ago
An 80.0 g sample of iodine-131 was placed in a sealed vessel forty days ago. Only 2.5 g of this isotope is now left. What is its
MA_775_DIABLO [31]
1.25, you divide 2.5 by 80, then times by 40
3 0
3 years ago
Read 2 more answers
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