All categories

3 years ago

A stalled car is pushed with a force of 342N from rest. How far does the car travel in 12 seconds if it’s mass is 989kg

Physics

1 answer:

allsm [11]3 years ago

6 0

24.89m

Explanation:

Given parameters:

Force on car = 342N

Initial velocity = 0

Time taken = 12s

Mass of the car = 989kg

Unknown:

Distance covered by the car = ?

Solution:

To solve this problem, we simply use one of the appropriates equations of motions.

s = ut + $\frac{1}{2}$ at²

s is the distance

u is the initial velocity

t is the time taken

a is the acceleration of the car.

To find the acceleration;

Acceleration = $\frac{Force }{mass}$ = $\frac{342}{989}$

Acceleration = 0.35m/s²

Inputting the parameters in the equation:

s = 0 x 12 + $\frac{1}{2}$ x 0.35 x 12² = 24.89m

Learn more:

Velocity brainly.com/question/10962624

#learnwithBrainly

You might be interested in

Hitungkan pecutan bagi blok di bawah: / Cal<br>(a)<br>m= 2 kg<br>F= 8.0 N

ioda

Answer:

Acceleration = 4 m/s²

Explanation:

Given the following data;

Force = 8 N

Mass = 2 kg

To find the acceleration of the block;

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

$Acceleration = \frac {Net \; force}{mass}$

Substituting into the formula, we have;

$Acceleration = \frac {8}{2}$

Acceleration = 4 m/s²

4 0

3 years ago

When touched by a plastic straw, the metal sphere will do what?

bearhunter [10]

I believe that if you touch a metal sphere with a plastic straw, the straw would not have enough strength to push it. So in that case, the metal sphere will not move and will stay in one place.

Please rate a 5 star

5 0

3 years ago

It is estimated that uranium is relatively common in the earth's crust, occurring in amounts of 4 g / metric ton. A metric ton i

timama [110]

Answer:

The mass of Uranium present in a 1.2mg sample is $4.8 \cdot 10^{-6}\,mg$

Explanation:

The ration between Uranium mass and total sample mass is: $\frac{4g}{1000kg} =\frac{4g}{1000000g}=\frac{1}{250000}$

For a sample of mass 1.2 mg, the amount of uranium is:

$1.2\, mg \cdot \frac{1}{250000}=4.8 \cdot 10^{-6}\,mg$

7 0

3 years ago

aluminum has a density of 2.7 g/cm3. if a chuck of aluminum with a mass of 16 g is placed in a graduated cylinder partially fill

sweet-ann [11.9K]

When placing the piece of aluminium in water, the level of water will rise by an amount equal to the volume of the piece of aluminum.
Therefore, we need to find the volume of that piece.

Density can be calculated using the following rule:
Density = mass / volume
Therefore:
volume = mass / density
we are given that:
the density = 2.7 g / cm^3
the mass = 16 grams
Substitute in the equation to get the volume of the piece of aluminum as follows:
volume = 16 / 2.7 = 5.9259 cm^3

Since the water level will rise to an amount equal to the volume of aluminum, therefore, the water level will rise by 5.9259 cm^3

5 0

3 years ago

To provide some perspective on the dimensions of atomic defects, consider a metal specimen that has a dislocation density of 105

-Dominant- [34]

Explanation:

LD₁ = 10⁵ mm⁻²

LD₂ = 10⁴mm⁻²

V = 1000 mm³

Distance = (LD)(V)

Distance₁ = (10⁵mm⁻²)(1000mm³) = 10×10⁷mm = 10×10⁴m

Distance₂ = (10⁹mm⁻²)(1000mm³) = 1×10¹² mm = 1×10⁹ m

Conversion to miles:

Distance₁ = 10×10⁴ m / 1609m = 62 miles

Distance₂ = 10×10⁹m / 1609 m = 621,504 miles.

7 0

3 years ago

Read 2 more answers