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daser333 [38]
3 years ago
8

A circus performer stretches a tightrope between two towers. He strikes one end of the rope and sends a wave along it toward the

other tower. He notes that it takes the wave 0.775 s to reach the opposite tower, 20.0 m away. If a 1 meter length of the rope has a mass of 0.300 kg, find the tension in the tightrope. N
Physics
1 answer:
IgorC [24]3 years ago
5 0

Explanation:

The given data is as follows.

      Distance (s) = 20 m

       time (t) = 0.775 s

Also, it is given that mass per 1 meter length (m) = 0.300 kg

Formula to calculate the velocity is as follows.

        Velocity (v) = \frac{s}{t}

Putting the given values into the above formula as follows.

              v = \frac{s}{t}

                 = \frac{20 m}{0.775 s}

                 = 25.80 m/s

We know that,

              v = \sqrt{\frac{T}{m}}

Taking square on both the sides, the formula will become as follows.

                      T = mv^{2}

                         = 0.3 kg \times 25.80          

                         = 199.692 N

Therefore, we can conclude that tension in the given tightrope is equal to 199.692 N .

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