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3 years ago

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A circus performer stretches a tightrope between two towers. He strikes one end of the rope and sends a wave along it toward the

other tower. He notes that it takes the wave 0.775 s to reach the opposite tower, 20.0 m away. If a 1 meter length of the rope has a mass of 0.300 kg, find the tension in the tightrope. N

1 answer:

IgorC [24]3 years ago

5 0

Explanation:

The given data is as follows.

Distance (s) = 20 m

time (t) = 0.775 s

Also, it is given that mass per 1 meter length (m) = 0.300 kg

Formula to calculate the velocity is as follows.

Velocity (v) = $\frac{s}{t}$

Putting the given values into the above formula as follows.

v = $\frac{s}{t}$

= $\frac{20 m}{0.775 s}$

= 25.80 m/s

We know that,

v = $\sqrt{\frac{T}{m}}$

Taking square on both the sides, the formula will become as follows.

T = $mv^{2}$

= $0.3 kg \times 25.80$

= 199.692 N

Therefore, we can conclude that tension in the given tightrope is equal to 199.692 N .

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Explanation:

I am assuming that you have to see which circuit has the greater current in this case. Well, this is the perfect example of Ohm's Law, which states the following -

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If one circuit has twice the voltage and half the resistance of the second circuit, as voltage is directly proportional to the resistance -

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Whereas in the second circuit -

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Answer:

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1W = 1J/s

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2 years ago

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Alexus [3.1K]

The complete question was calculate the period T assuming the smallest amplitude.
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3 years ago

Please help me with this question

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Answer:

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(5) 7 A

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(4)

From the diagram,

A = 3+6+2

A = 11 A

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A₂ = V/R₂............ Equation 1

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Substitute these values into equation 1

A₂ = 12/4

A₂ = 3 A

(5) Applying,

V = IR'

I = V/R'............ Equation 1

Where V = Voltage, I = cuurent, R' = total resistance.

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2 years ago

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denis23 [38]

Explanation:

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