Answer:
Circuit one will have more current than circuit two
Explanation:
I am assuming that you have to see which circuit has the greater current in this case. Well, this is the perfect example of Ohm's Law, which states the following -
V = IR,
where V = voltage / potential difference, I = current, and R = resistance
If one circuit has twice the voltage and half the resistance of the second circuit, as voltage is directly proportional to the resistance -
2V = I( 1 / 2R ),
4V = IR,
I = 4V / R
Whereas in the second circuit -
V = IR,
I = V / R
As you can note, voltage is directly proportional to the current ( I ) as well as the resistance. The only difference between the two formulas I = 4V / R, and I = V / R is the difference in the voltage. With the voltage being 4 times greater in the first circuit, and current is 4 times greater in the first circuit as well.
<u><em>Hence, circuit one will have more current than circuit two</em></u>
The complete question was calculate the period T assuming the smallest amplitude.
Using the equation;
T = 2 π√(L/g)
Where T is the period in seconds, L is the length of the rod or wire in meters and g is the acceleration due to gravity.
Hence; T = 2×3.14 × √(2/9.81)
= 6.28 × 0.4515
= 2.836 seconds
Answer:
(4) A = 3 A, A₂ = 11 A
(5) 7 A
Explanation:
(4)
From the diagram,
A = 3+6+2
A = 11 A
V = A₂R
A₂ = V/R₂............ Equation 1
Given: V = 12 V, R₂ = 4 Ω
Substitute these values into equation 1
A₂ = 12/4
A₂ = 3 A
(5) Applying,
V = IR'
I = V/R'............ Equation 1
Where V = Voltage, I = cuurent, R' = total resistance.
But,
1/R' = (1/3)+(1/4)
1/R' = (3+4)/12
1/R' = 7/12
R' = 12/7 Ω
Given: V = 12 V
Substitute these values into equation 1
I = 12/(12/7)
I = 7 A
Therefore
A = 7 A
Explanation:
According to the energy conservation,



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= 
v = 
= 
Formula for distance from the orbit is as follows.
S = 
= 
= 
Now, relation between time and distance is as follows.
T = 

or, f =
=
= 
Thus, we can conclude that the orbital frequency for an electron and a positron that is 1.50 apart is
.