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3 years ago

How many neutrons does element X have if its atomic number is 48 and its mass number is 167?

Physics

1 answer:

Black_prince [1.1K]3 years ago

7 0

You would have to subtract the mass number with atomic number which will give you 119 number of neutrons.

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A steel ball bearing with a radius of 1.5 cm forms an image of an object that has been placed 1.1 cm away from the bearing’s sur

Nonamiya [84]

Answer:

Check the explanation

Explanation:

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

The image is virtual

The image is upright

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

Kindly check the diagram in the attached image below.

5 0

3 years ago

A group of a few thousand stars that are loosely held together by gravity is called a

zalisa [80]

Would it be an open cluster

8 0

3 years ago

A 190 N child is in a swing that is attached to ropes 2.10 m long. Find the gravitational potential energy of the child-Earth sy

Alekssandra [29.7K]

Answer:

a) Gravitational potential energy = 399 J

b) Gravitational potential energy = 66.5 J

c) Gravitational potential energy = 0 J

Explanation:

Hi there!

Please, see the attached figure for a better understanding of the problem.

a) When the ropes are horizontal, the height of the child, relative to the child's lowest position, is 2.10 m (see figure).

The gravitational potential energy is calculated as follows:

PE = mgh

Where:

PE = potential energy.

mg = weight of the child

h = height.

Then when the ropes are horizontal, the potential energy will be:

PE = 190 N · 2.10 m = 399 J

b) When the ropes make a 34.0° with the vertical, the height of the child is 2.10 m minus x (see figure). To find x, we can use trigonometry of right triangles:

cos angle = adjacent side / hypotenuse

cos 34.0° = x / 2.10 m

x = 2.10 m · cos 34.0° = 1.75 m

Then, the height of the child relative to the lowest position is

(2.10 m - 1.75 m) = 0.35 m

Therefore, the gravitational potential energy will be:

PE = 190 N · 0.35 m

PE = 66.5 J

c) When the child is at the bottom of the circular arc the height is zero (the child is at the lowest position), then, the gravitational potential energy will be zero.

6 0

3 years ago

Whether an ionic bond or a covalent bond forms, bonds form in order to make newly created substances ________ than the substance

Nezavi [6.7K]

The answer would be less stable

6 0

3 years ago

In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, th

Georgia [21]

Explanation:

Given that,

Frequency in the string, f = 110 Hz

Tension, T = 602 N

Tension, T' = 564 N

We know that frequency in a string is given by :

$f=\dfrac{1}{2L}\sqrt{\dfrac{T}{m/L}}$ , T is the tension in the string

i.e.

$f\propto\sqrt{T}$

$\dfrac{f}{f'}=\sqrt{\dfrac{T}{T'}}$ , f' is the another frequency

${f'}=f\times \sqrt{\dfrac{T'}{T}}$

${f'}=110\times \sqrt{\dfrac{564}{602}}$

f' =106.47 Hz

We need to find the beat frequency when the hammer strikes the two strings simultaneously. The difference in frequency is called its beat frequency as :

$f_b=|f-f'|$

$f_b=|110-106.47|$

$f_b=3.53\ beats/s$

So, the beat frequency when the hammer strikes the two strings simultaneously is 3.53 beats per second.

8 0

3 years ago