This would be B
Hope this helped
Period = (1) / (frequency)
Period = (1) / (200 per second) = 0.005 second = 5 milliseconds
Answer:OB=58.3m
Explanation:
So here cow wanders 30m in north and turns 22 degrees in right side and moves 40m more, as shown in figure given.
now take the starting point as a origin such that cow moves in x-y co-ordinate axis.
As shown in figure length OA is the length when cow moves in north or y direction. Later she takes 22 degrees turn to right and moves 40m more.
So the final displacement is the length of cow from the origin that is length OB.
now co-ordinates of B are [40cos22°,40sin22°+30] i.e [37.084,44.984]
now displacement of cow= length of OB
= ![\sqrt{[37.084]^{2}+[44.984]^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5B37.084%5D%5E%7B2%7D%2B%5B44.984%5D%5E%7B2%7D%20%20%7D)
=
OB =
Hello,
Here is your answer:
The proper answer for this question is option B "When released,a book falls to the ground". That's because of gravity the book will hit the ground!
Your answer is B.
If you need anymore help feel free to ask me!
Hope this helps.
Answer:
The speed of the ball is 42.5 m/s
Explanation:
The initial kinetic energy of the ball is:
= 85.75 J
The speed of the ball after leaving the bat is:

V=47.92 m/s
Using kinematic equation we can find the speed of the ball after being 25 m above the point of collision:




