<img src="https://tex.z-dn.net/?f=%5Chuge%5Cmathfrak%7BQuestion%3A-%7D" id="TexFormula1" title="\huge\mathfrak{Question:-}" alt=

All categories

Sholpan [36]

2 years ago

"\huge\mathfrak{Question:-}" align="absmiddle" class="latex-formula">
Why does time seem to flow only in one direction?

Physics

2 answers:

Thepotemich [5.8K]2 years ago

5 0

Time seem to flow only in one direction because if it started to go in backward direction that would break the second law of thermodynamics. We do not find time to be moving in any direction because time is not an object that can move nor is it a force that can move any object.

lbvjy [14]2 years ago

3 0

Answer:

hii how are you.

apka naam kya hai Aur age apki please tell me.

where are you from.

You might be interested in

A sound wave traveling through a solid material has a frequency of 400 hertz. the wavelength of the sound wave is 2 meters. what

Pepsi [2]

Answer:

c. 800m/s

Explanation:

v = f × /\

v = 400 × 2

v = 800m/s

3 0

3 years ago

Gravitational force is determined by which of the following

hram777 [196]

Gravitational force is determined by mass

Answer: Option B

Explanation:

According to Universal law of gravity, the gravitational force is directly proportional to the product of the masses of the objects and inversely proportional to the square of the distance between the objects.

$F=G \times \frac{m_{1} \times m_{2}}{r^{2}}$

Where,

G – gravitational constant = $\text { 6. } 67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2}$

$\boldsymbol{m}_{1}, \boldsymbol{m}_{2}$ = masses of two objects

r – distance between the objects

So, as per this law, the gravitational force is found by mass.

8 0

3 years ago

Two runners start at the same point on a straight track. The first runs with constant acceleration so that he covers 98 yards in

charle [14.2K]

Answer:

94.13 ft/s

Explanation:

Given:

$t$ = time interval in which the rock hits the opponent = 10 s - 5 s = 5 s

$s$ = distance to be moved by the rock long the horizontal = 98 yards

$y$ = displacement to be moved by the rock during the time of flight along the vertical = 0 yard

Assume:

$u$ = magnitude of initial velocity of the rock

$\theta$ = angle of the initial velocity with the horizontal.

For the motion of the rock along the vertical during the time of flight, the rock has a constant acceleration in the vertically downward direction.

$\therefore y = u\sin \theta t +\dfrac{1}{2}(-g)t^2\\\Rightarrow 0 = u\sin \theta 5 +\dfrac{1}{2}(-9.8)\times 5^2\\\Rightarrow u\sin \theta 5 =\dfrac{1}{2}(9.8)\times 5^2......(1)\\$

Now the rock has zero acceleration along the horizontal. This means it has a constant velocity along the horizontal during the time of flight.

$\therefore u\cos \theta t = s\\\Rightarrow u\cos \theta 5 = 98.....(2)\\$

On dividing equation (1) by (2), we have

$\tan \theta = \dfrac{25}{20}\\\Rightarrow \tan \theta = 1.25\\\Rightarrow \theta = \tan^{-1}1.25\\\Rightarrow \theta = 51.34^\circ$

Now, putting this value in equation (2), we have

$u\cos 51.34^\circ\times 5 = 98\\\Rightarrow u = \dfrac{98}{5\cos 51.34^\circ}\\\Rightarrow u =31.38\ yard/s\\\Rightarrow u =31.38\times 3\ ft/s\\\Rightarrow u =94.13\ ft/s$

Hence, the initial velocity of the rock must a magnitude of 94.13 ft/s to hit the opponent exactly at 98 yards.

3 0

3 years ago

On the EM spectrum, visible light is found between

stich3 [128]

Visible light is found between infrared rays (lower frequency, higher wavelength) and ultraviolet rays (higher frequency, lower wavelength). This the spectrum of light that we are able to see reflected back at us, and is also the spectrum of color that we are able to see.

Answer is D

3 0

3 years ago

Read 2 more answers

Car A is traveling west at 40 mi/h and car B is traveling north at 40 mi/h. Both are headed for the intersection of the two road

Gwar [14]

Explanation:

It is given that,

$\frac{dx}{dt}$ = -40 mi/h, $\frac{dx}{dt}$ = -40 mi/h