<u>Answer:</u> The solubility of ethylene gas in water is
<u>Explanation:</u>
To calculate the molar solubility, we use the equation given by Henry's law, which is:
where,
= Henry's constant =
= molar solubility of ethylene gas = ?
= partial pressure of ethylene gas = 0.684 atm
Putting values in above equation, we get:
Converting this into grams per liter, by multiplying with the molar mass of ethylene:
Molar mass of ethylene gas = 28 g/mol
So,
Hence, the solubility of ethylene gas in water is
It is 3 moles. Don't doubt urself
We have that the the molarity of methanol in the solution is mathematically given as
Morality=7.91mol/l
<h3>
Chemical Reaction</h3>
Question Parameters:
An <u>aqueous </u><em>solution </em>of methanol (MM = 32.04 g/mol)
A molality of 8.83 m and a density of 1.15 g/mL.
Generally the equation for the is mathematically given as
where
Mass of solution=(100+282.2)
Mass of solution=1289.9
Volume=1289.9/1.15
Volume=1.115L
Therefore
Morality=8.83/1.115
Morality=7.91mol/l
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