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Lilit [14]
3 years ago
13

What does how will u experiment mean in making a science project

Chemistry
1 answer:
Lady_Fox [76]3 years ago
7 0
How are you going to experiment means how will you show your project in a real life situation like a penny being cleaned with different acids.
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The larger oxygen atom, with more protons, is more ____________ than the hydrogen atom and attracts the electron pair closer.
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<span>Electronegative. Electronegativity is the tendency for an atom to pull more electrons. Fluroine is the most electronegative element, and the trend is up and to the right of the periodic table, with the exception of the noble gases.</span>
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Panuto: Punan ang talaan sa ibaba at suriing mabuti ang sarili upang higit mong
Novay_Z [31]
The answer is 2

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3 years ago
A steam engine (assume a Carnot engine ) has an efficiency of 50.8%. If the waste heat has a temperature of 72.4 ◦C, what is the
Inessa05 [86]

Answer:

The temperature of the boiler is approximately 147.1 °C

Explanation:

A Carnot engine is an ideal engine that has the highest efficiency among all the engines because the second law of thermodynamics.That efficiency \eta  is:

\eta=1-\frac{T_{c}}{T_{h}}

with T_{h} the temperature of the hot reservoir (the boiler temperature) and T_{c} the temperature of the cold reservoir (the steam temperature). Solving for T_{h}:

T_{h}=\frac{-T_{c}}{\eta-1}=\frac{-72.4}{0.508-1}\approx147.1\,C

3 0
3 years ago
Mercury’s atomic emission spectrum is shown below. Estimate the wavelength of the orange line. What is its frequency? What is th
lions [1.4K]

The wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.

<em>"Your question is not complete, it seems to be missing the diagram of the emission spectrum"</em>

the diagram of the emission spectrum has been added.

<em>From the given</em><em> chart;</em>

The wavelength of the atomic emission corresponding to the orange line is 610 nm = 610 x 10⁻⁹ m

The frequency of this emission is calculated as follows;

c = fλ

where;

  • <em>c is the speed of light = 3 x 10⁸ m/s</em>
  • <em>f is the frequency of the wave</em>
  • <em>λ is the wavelength</em>

f = \frac{c}{\lambda } \\\\f = \frac{3\times 10^8}{610 \times 10^{-9}} \\\\f = 4.92 \times 10^{14} \ Hz

The energy of the emitted photon corresponding to the orange line is calculated as follows;

E = hf

where;

  • <em>h is Planck's constant = 6.626 x 10⁻³⁴ Js</em>

<em />

E = (6.626 x 10⁻³⁴) x (4.92 x 10¹⁴)

E = 3.26 x 10⁻¹⁹ J.

Thus, the wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.

Learn more here:brainly.com/question/15962928

6 0
2 years ago
And I living organism what is a tissue
Leviafan [203]
It is an ensemble of similar cells
4 0
3 years ago
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