Answer:
The types of Asexual reproduction include: fission, fragmentation, budding, vegetative reproduction, spore formation and agamogenesis.
Answer:
d) PO4^3-, HPO4^2-
Explanation:
Basically, an acid and a base which differs only by the presence or absence of proton (hydrogen ion) are called a conjugate acid-base pair.
a) HI, I
This is incorrect. For the acid, HI the conjugate base is I⁻ ion.
b) HCHO2, SO4^2-
This is incorrect, there's no relationship between both entities.
c) CO3^2-, HCI
This is incorrect, there's no relationship between both entities.
d) PO4^3-, HPO4^2-
This is correct. The difference between both entities is the Hydrogen ion. This is the conjugate acid-base pair
Answer:
C. Yes, if each sample contains 6.02 x 10²³ atoms.
Explanation:
It is possible for each sample to contain 1 mole of each sample if and only if each of the sample if made up of 6.02 x 10²³ atoms.
6.02 x 10²³ atoms is the Avogadro's number. This number is equivalent to a mole of a substance.
- If the amount of matter in the given substance is at least one mole, it is possible that they are made up of one mole each of each substance.
- If they contain lesser amount of atoms, then it is not up to one mole of substance.
- But if it is greater, then, we can have even more than one mole of substance.
A mole is simply a unit of measurement and it is equivalent to 6.02 x 10²³ atoms.
A mixture of oil and water is:
Heterogeneous
immiscible
<h3>What type of mixture of oil and water is?</h3>
The water molecules attract each other, and the oil molecules stick together. That causes oil and water to form two separate layers. Water molecules pack closer together, so they sink to the bottom, leaving oil sitting on top of the water. The mixture can be called as Emulsion. It is an immiscible liquid and the mixture is heterogeneous as oil floats on top of water surface but do not mix with it.
Thus, correct options are Heterogeneous and immiscible.
Find more information about Mixture here:
brainly.com/question/498370
The grams of potassium chlorate that are required to produce 160 g of oxygen is 408.29 grams
<u><em>calculation</em></u>
2 KClO₃→ 2 KCl + 3O₂
Step 1: find the moles of O₂
moles = mass÷ molar mass
from periodic table the molar mass of O₂ = 16 x2 = 32 g/mol
moles = 160 g÷ 32 g/mol = 5 moles
Step2 : use the mole ratio to determine the moles of KClO₃
from equation given KClO₃ : O₂ is 2:3
therefore the v moles of KClO₃ = 5 moles x 2/3 = 3.333 moles
Step 3: find the mass of KClO₃
mass= moles x molar mass
from periodic table the molar mass of KClO₃
= 39 + 35.5 + (16 x3) =122.5 g/mol
mass = 3.333 moles x 122.5 g/mol =408.29 grams
