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3 years ago

Given that earth orbits at 150,000,000 km from the sun, through what distance does earth move in a second?

Physics

1 answer:

Murrr4er [49]3 years ago

3 0

First we know that Earth moves around the sun once per year.

If Radius = 150,000,000Km, then the circumference of Earth's orbit must be:

C = 2 x R x Pi

C = 2 x 150,000,000 x 3.141529

C = 942,458,700Km per year

Divide that by 365.25 days, and we get:

C = 2,580,311Km per day

Further divide that by 24 hours and we get:

C = 107,512Km / hour

There are 3600 seconds in an hour so:

C = 29.86 km / second

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3 years ago

Force F acts between a pair of charges, q1 and q2, separated by a distance d. For each of the statements, use the drop-down menu

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1. F

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So, the new force is:

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2. F/4

In this case, q1 and q2 are unchanged. The distance between the charges is doubled to 2d.

So, we have:

$q_1' = q_1\\q_2' = q_2\\d' = 2d$

So, the new force is:

$F'=k \frac{q_1' q_2'}{d'^2}= k \frac{q_1 q_2)}{(2d)^2}=\frac{1}{4} k \frac{q_1 q_2}{d^2}=\frac{F}{4}$

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So, the new force is:

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So the force has increased by a factor 6.

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3 years ago

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