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3 years ago

The player that possess the best ball handling skills and usually handles the ball often

Physics

1 answer:

velikii [3]3 years ago

4 0

The player that possess the best ball handling skills and usually handles

the ball often is referred to as the point guard.

Point guards in basketball are referred to as the players who have certain

characteristics such as speed ,an excellent ball handling skills and

leadership qualities.

Point guards is similar to the creative midfielder in soccer which helps to

dictate play and create chances for other team mates which is why they

handle the ball often.

Read more on brainly.com/question/25759951

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A 20 ohm lamp and a 5 ohm lamp are connected in series and placed across a potential difference of 50 V.

iogann1982 [59]

Hi there!

Since the two resistors are in series, we can simply add:
$R_T = R_1 + R_2 + ... R_n$

$R_T = 20 + 5 = \boxed{25 \Omega}$

In series, the potential difference of each resistor (lamp) ADDS UP. We can begin by finding the current through the circuit using Ohm's law:
$V = IR\\\\I = \frac{V}{R_T}$

Plug in the values:
$I = \frac{50}{25} = 2 A$

Now,

we can use Ohm's law to find the individual voltage for each lamp.

20 Ohm lamp:
$V = 2 * 20 = \boxed{40 V}$

5 Ohm lamp:
$V = 2 * 5 = \boxed{10 V}$

To solve, we can use the power equation.

$P (\text{Watts})= IV$

Plug in the values for each.

20 Ohm lamp:
$P = 2 * 40 = \boxed{80 W}$

5 Ohm lamp:
$P = 2 * 10 = \boxed{100 W}$

7 0

2 years ago

Un cuerpo gira con movimiento circular uniforme un ángulo total de 1080° en 20

LekaFEV [45]

Velocidad angular = (angulo total) / (tiempo total)

Velocidad angular = (1080 grados) / (20 segundos)

Velocidad angular = (1080/20) g/s

Velocidad angular = 54 g/s

Pero 180 grados = π radianes

V.A. = (54 g/s) x (π rad / 180 g)

V.A. = (54π gr-rad / 180 seg-gr)

V.A. = aproximadamente 0.942 rad/seg

7 0

3 years ago

If a diffraction grating has 3700 lines per cm, what is the spacing d between lines

Sonja [21]

So first we find the gap between the slits by the formula d=1/N

<span>N is number of lines per metre so 3700 line/cm = 370000 lines/m </span>
<span>So d=2.7*10^-6 </span>

<span>Now we use the formula dsin(angle)=n(wavelength) </span>

<span>d is the same </span>
<span>n is the order of the diffraction pattern </span>

<span>so wavelenth=dsin(angle)/n </span>
<span>=[(2.7*10^-6)*sin30]/3 </span>
<span>=4.5*10^-7 m</span>

7 0

3 years ago

A person doing chin-up weighs 700.0 N, disregarding the weight of the arms. During the first 25.0 cm of the lift, each arm exert

dlinn [17]

First, we will get the resultant force:
The direction of the force due to the person's weight is vertically down.
weight of person = 700 newton

Assume that the force exerted by the arms has a vertically upwards direction.
Force exerted by arms = 2*355 = 710 newtons

Therefore, the resultant force = 710 - 700 = 10 newtons (in the vertically upwards direction)

Now, we will get the mass of the person.
weight = 700 newtons
weight = mass * acceleration due to gravity
700 = 9.8*mass
mass = 71.428 kg

Then we will calculate the acceleration of the resultant force:
Force = mass*acceleration
10 = 71.428*acceleration
acceleration = 0.14 m/sec^2

Finally, we will use the equation of motion to get the final speed of the person.
V^2 = U^2 + 2aS where:
V is the final velocity that we need to calculate
U is the initial velocity = 0 m/sec (person starts at rest)
a is the person's acceleration = 0.14 m/sec^2
S is the distance covered = 25 cm = 0.25 meters

Substitute with the givens in the above equation to get the final speed as follows:
V^2 = U^2 + 2aS
V^2 = (0)^2 + 2(0.14)(0.25)
V^2 = 0.07
V = 0.2645 m/sec

Based on the above calculations:
The person's speed at the given point is 0.2645 m/sec

4 0

3 years ago

Read 2 more answers

A teacher told a learner to react benzene (CH) with chlorine (Cl₂) to

kolezko [41]

The minimum quantity of benzene, C₆H₆ needed for the reaction is 106.67 g

<h3>How to determine the theoretical yield of chlorobenzene, C₆H₅Cl</h3>

From the question given, the following data were obtained

Actual yield = 100 g
Percentage yield = 65%
Theoretical yield =?

Percentage yield = (Actual / Theoretical) × 100

65% = 100 / Theoretical

0.65 = Actual / Theoretical

Cross multiply

0.65 × Theoretical = 100

Divide both sides by 0.65

Theoretical = 100 / 0.65

Theoretical yield = 153.85 g

<h3>How to determine the mass of benzene, C₆H₆ needed</h3>

Balanced equation

C₆H₆ + Cl₂ → C₆H₅Cl + HCl

Molar mass of C₆H₆ = 78 g/mol

Mass of C₆H₆ from the balanced equation = 1 × 78 = 78 g

Molar mass of C₆H₅Cl = 112.5 g

Mass of C₆H₅Cl from the balanced equation = 1 × 112.5 = 112.5 g

SUMMARY

From the balanced equation above,

112.5 g of C₆H₅Cl were obtained from 78 g of C₆H₆

Therefore,

153.85 g of C₆H₅Cl will be produced from = (153.85 × 78) / 112.5 = 106.67 g of C₆H₆

Thus, the minimum amount of benzene, C₆H₆ needed for the reaction is 106.67 g

Learn more about stoichiometry:

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3 0

2 years ago