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3 years ago

Question 5

Chemistry

1 answer:

bagirrra123 [75]3 years ago

3 0

Answer:

true

Explanation:

any object that is larger will take a longer time to do things, the same applies to heat levels. The lower the heat, the longer it takes, the higher the heat, the shorter it takes. So if an iceberg is large, it will need a higher heat, whereas an ice cube is really small and doesn't need that much heat to melt.

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Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2NH3(g) 3N2O(g)4N2(g) 3H2O

trasher [3.6K]

Answer: $\Delta H^{0} = -879.15 kJ/mol$

Explanation: Heats of formation is the amount of heat necessary to create 1 mol of a compound from its molecular constituents. The basic conditions the substance is formed is at standard conditions: 1 atm and 25°C. Each compound has its own heat of formation per mol of compound (kJ/mol), but to an element is assigned a value of zero.

Standard Enthalpy Change is defined as the heat absorbed or released when a reaction takes place. It can be positive or negative, which means reaction is endothermic or exothermic, respectively.

Enthalpy change is calculated as the difference between the sum of heat formation of products and the sum of heat formation of the reactants:

$\Delta H^{0}=\Sigma H^{0}_{f}_{(products)}-\Sigma H^{0}_{f}_{(reactants)}$

For the reaction

2NH₃ + 3N₂O → 4N₂ + 3H₂O

2(-46.2) + 3(82.05) 4(0) + 3(-241.8)

$\Delta H^{0}=3(-241.8)-[ 2(-46.2)+3(82.05)]$

$\Delta H^{0}=-725.4-153.75$

$\Delta H^{0}=-879.15$

The standard enthalpy change for the reaction is $\Delta H^{0}=-879.15$ kJ

8 0

3 years ago

the molar enthalpy of formation of carbondioxide is -393kjmol. calculate the heat released by the burning of 0.327g of carbon to

Arte-miy333 [17]

This is equivalent to having a standard enthalpy change of reaction equal to 10.611 kJ

Explanation:

The standard enthalpy change of reaction, Δ H ∘ , is given to you in kilojoules per mole, which means that it corresponds to the formation of one mole of carbon dioxide.

C (s] + O 2(g] → CO 2(g]

Remember, a negative enthalpy change of reaction tells you that heat is being given off, i.e. the reaction is exothermic.

First to convert grams of carbon into moles,

use carbon's molar mass(12.011 g).

Moles of C = mass in gram / molar mass

= 0.327 g / 12.011 g

Moles of C = 0.027 moles

Now, in order to determine how much heat is released by burning of 0.027 moles of carbon to form carbon-dioxide.

= 0.027 moles C $\times$ 393 kJ

Heat released = 10.611 kJ.

So, when 0.027 moles of carbon react with enough oxygen gas, the reaction will give off 10.611 kJ of heat.

This is equivalent to having a standard enthalpy change of reaction equal to 10.611 kJ

7 0

3 years ago

What is the process for extracting oils

OLEGan [10]

Answer:

Oil is extracted by three general methods: rendering, used with animal products and oleaginous fruits; mechanical pressing, for oil-bearing seeds and nuts; and extracting with volatile solvents, employed in large-scale operations for a more complete extraction than is possible with pressing.

Explanation:

4 0

3 years ago

The rate constant of a reaction is 6.90 Ã 10â5 l/molÂ·s at 195Â°c and 6.00 Ã 10â3 l/molÂ·s at 258Â°c. what is the activation ene

kap26 [50]

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3 years ago

Calculate the mass of butane needed to produce 97.4 g of carbon dioxide. Express your answer to three significant figures and in

Vsevolod [243]

Answer:

32.1 g

Explanation:

Step 1: Write the balanced combustion reaction

C₄H₁₀ + 6.5 O₂ ⇒ 4 CO₂ + 5 H₂O

Step 2: Calculate the moles corresponding to 97.4 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

97.4 g × 1 mol/44.01 g = 2.21 mol

Step 3: Calculate the moles of butane that produced 2.21 moles of carbon dioxide

The molar ratio of C₄H₁₀ to CO₂ is 1:4. The moles of C₄H₁₀ required are 1/4 × 2.21 mol = 0.553 mol

Step 4: Calculate the mass corresponding to 0.553 moles of C₄H₁₀

The molar mass of C₄H₁₀ is 58.12 g/mol.

0.553 mol × 58.12 g/mol = 32.1 g

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3 years ago