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Volgvan
3 years ago
12

Determine the heat energy required to vaporize 13.9 grams of liquid water at 100° C. O 2,006 cal O 47.8 cal O 7,506 cal O 24.9 c

al
Physics
1 answer:
Harlamova29_29 [7]3 years ago
6 0

Answer:

7506 cal

Explanation:

Given: Mass of water = m = 13.9 grams.

Heat energy required to determine the conversion of 13.9 grams of water to steam or vapor is m L,

where L = Latent heat of vaporization of water=540 cal/g.

Q = mL = (13.9)(540) = 7,506 cal.

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Answer:

m = 1.26*10²⁵ kg.

Explanation:

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We have the total time since the stone was thrown upwards, not the one used for the upward trajectory.

It can be showed, using the expression for the displacement (which is the same in both directions) that the time used for going up, it's the same used to go down, so the time that we need to put in (1). is just the half of the total time.

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With this value for  rp, we can solve (2) for mp, as follows:

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8 0
3 years ago
Determine e when I = 0.50 A and R = 12 W.
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Answer:

The correct answer is "24 V".

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