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Fudgin [204]
3 years ago
15

Shani poses as the statue of liberty for an art class. she holds a torch above her head with her right hand and a book against h

er side with her left hand. she holds the pose for ten minutes. at the end of the session, she mentions to her friend that it was a lot of work to pose and that her arms are really tired.which describes the work shani did while she posed?
Physics
1 answer:
kozerog [31]3 years ago
6 0
For Art class, Social Studies class, English class, American History class,
or Photography class, Shani has done an incredible amount of work. 
She'll tell her parents all about it at dinner, and her arms will really ache
when she gets up tomorrow morning.

But it's a different story in Physics class.  In Physics, there is a formal definition
for "work".  (That's so it can be measured, and numerically compared to all forms
of energy.) 

The scientific definition of work is 

                           (force exerted) times (distance moved) .

With this definition, if the force doesn't move through a distance,
then the work done is zero. 

Anything you do without moving, even if it's holding a small car over
your head for an hour while your muscles tremble and sweat pours
down, represents no "work" in the scientific sense.
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A space probe lands on a newly discovered planet. A small canister is released from the probe and falls a distance of 3 m in 0.5
ivanzaharov [21]

Answer:

24m/s²

Explanation:

Given

Distance S = 3m

Time of fall = 0.5sec

Required

Acceleration due to gravity

Using the equation of motion

S = ut+1/2gt²

Substitute the given values

3 = 0+1/2g(0.5)²

3 = 1/2(0.25)g

3 = 0.125g

g = 3/0.125

g = 24

Hence the value for the acceleration of gravity on this new planet is 24m/s²

3 0
2 years ago
two forces whose magnitude are in ratio of 3:5 gives a resultant of 35N.if the angle of inclination is 60degree.calculate the ma
nadya68 [22]

Answer:

the magnitude of first force = 3 × 5= 15 N

ANd, the magnitude of second force = 5 × 5 = 25 N

Explanation:

The computation of the magnitude of the each force is shown below:

Provided that

Ratio of forces = 3: 5

Let us assume the common factor is x

Now

first force =  3x

And, the second force = 5x

Resultant force = 35 N

The Angle between the forces = 60 degrees  

Based on the above information

Resultant force i.e. F = √ F_1^2 +F_2^2 + 2 F_1F_2cos\theta

35 = √[(3x)²+ (5x)²+ 2 (3x)(5x) cos 60°]

 35 =√ 9x² + 25x² + 15x²    (cos 60° = 0.5)

35 = √49 x²

 x = 5

So, the magnitude of first force = 3 × 5= 15 N

ANd, the magnitude of second force = 5 × 5 = 25 N

7 0
3 years ago
In order to generate electricity from mechanical energy,one essential element needed to transform the energy into electrical ene
s344n2d4d5 [400]

Answer:

Magnet or magnetic field

Explanation:

5 0
3 years ago
A proton moving at 3.0 × 10^4 m/s is projected at an angle of 30° above a horizontal plane. If an electric field of 400 N/C is a
GuDViN [60]

Answer:

The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s

Explanation:

From Newton's second law, F = mg and also from coulomb's law F= Eq

Dividing both equations by mass;

F/m = Eq/m = mg/m, then

g = Eq/m --------equation 1

Again, in a projectile motion, the time of flight (T) is given as

T = (2usinθ/g) ---------equation 2

Substitute in the value of g into equation 2

T = \frac{2usin \theta}{\frac{Eq}{m}} =\frac{m* 2usin \theta}{Eq}

Charge of proton = 1.6 X 10⁻¹⁹ C

Mass of proton = 1.67 X 10⁻²⁷ kg

E is given as 400 N/C, u = 3.0 × 10⁴ m/s and θ = 30°

Solving for T;

T = \frac{(1.67X10^{-27}* 2*3X10^4sin 30}{400*1.6X10^{-19}}

T = 7.83 X10⁻⁷ s

6 0
3 years ago
How much work is accomplished when a force of 250 N pushes a box across the floor for a distance of 50 meters?
mote1985 [20]
We use the work formula to solve for the unknown in the problem. The formula for work is expressed as the product of the net force and the distance traveled by the object. We were given both the force and the distance so we can solve work directly.

Work = 250 N x 50 m = 12500 J

Thus, the answer is C.
7 0
3 years ago
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