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blsea [12.9K]
2 years ago
10

The bonding and molecular polarity in a molecule of Cl2 is best described as...

Chemistry
1 answer:
matrenka [14]2 years ago
6 0

Answer:

<em>The </em><em>bonding</em><em> </em><em>and</em><em> </em><em>molecular </em><em>polarity </em><em>in </em><em>a </em><em>molecule </em><em>of </em><em>CI2 </em><em>is </em><em>best</em><em> </em><em>described </em><em>as </em><em>palar </em><em>/</em><em> </em><em>polar</em>

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Determine the mass of carbon iv oxide ,produced on burning 104g of ethyne​
mars1129 [50]

163 grams (3 sig. fig.).

<h3>Explanation</h3>
  • Formula of <em>carbon(IV) oxide</em> (a.k.a. carbon dioxide): \text{CO}_2.
  • Molar mass of \text{CO}_2: \underbrace{12.01}_{\text{C}} + 2\times\underbrace{16.00}_{\text{O}}=44.01\;\text{g}\cdot\text{mol}^{-1}.
  • Formula of ethyne: structural \text{H}-\text{C}\equiv\text{C}-\text{H} or molecular \text{C}_2\text{H}_2.
  • Molar mass of \text{C}_2\text{H}_2: 2\times\underbrace{12.01}_{\text{C}}+2 \times\underbrace{16.00}_{\text{O}} = 56.02\;\text{g}\cdot\text{mol}^{-1}.

All carbon atoms in that 104 grams of ethyne will end up in \text{CO}_2. Number of moles of molecules in 104 grams of ethyne:

n = \dfrac{m}{M} = \dfrac{104}{56.02} = 1.85648\;\text{mol}.

There are two carbon atoms in each ethyne molecule. Number of carbon atoms in that many ethyne molecules:

n(\text{C}) = 2\;n(\text{C}_2\text{H}_2) = 3.71296\;\text{mol}.

There are one carbon atom in each \text{CO}_2 molecule. In case oxygen is in excess, all those carbon atoms from that 104 grams of ethyne will make n(\text{CO}_2) = n(\text{C}) =3.71296\;\text{mol} of \text{CO}_2.

Mass of all those \text{CO}_2 molecules:

m = n\cdot M = 163\;\text{g}. (3 sig. fig. as in the mass of ethyne.)

7 0
3 years ago
Question 11 (1 point)
erastova [34]

Answer:

remove product

Explanation:

Removing the product will always shift the equilibrium to the right. This is based on the Le Chatelier's principle which states that "if any of the conditions of a system in equilibrium is changed, the system will adjust itself in order to annul the effect of the change".

  • If a system at equilibrium is disturbed, by changing the concentration of one of the substances all the concentrations will change until a new equilibrium point is reached.
  • Removing the product will increase the concentration of the species on the left hand side, the equilibrium will shift to the right.
5 0
3 years ago
Which of the following is the correct formula for barium (II) sulfate?
nasty-shy [4]
BaSO4 is the correct formula for barium (ll) sulfate
5 0
3 years ago
Read 2 more answers
Balance the following equations:
lesya [120]
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2>

(I) N_{2} + 3H_{2} --> 2NH_{3}

(II) P_{4}  + 5O_{2}  --> 2P_{2} O_{5}

(III) 2NaF + Br_{2}  -->2NaBr + F_{2}

(IV) 2ZnS + 3O_{2} --> 2ZnO + 2SO_2

(V) Pb(NO_3)_2 + 2NaCl --> 2NaNO_3 + PbCl_2

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

7 0
2 years ago
Reaction of acetylene with silver nitrate​
MAVERICK [17]

Answer:

*boom*

Explanation:

..... ;) jkjk .......

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3 years ago
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