Answer:
The vertex for parabola y²=4ax is (0,0)
and for (y-k) ²= 4a(x+h), vertex is (h, k).
But you have not given the equation of parabola in the equation.
<em>You would use AAS because of the fact that there is two angles and the angle where both triangles instersect and create a verticle angle, there is no angle written. It has an angle then another angle then a side. Hope this helps!</em>
9514 1404 393
Answer:
26 square units
Step-by-step explanation:
Counting grid squares on the graph, we see that segment AB is the hypotenuse of a right triangle with legs 2 and 3. Its length is ...
AB = √(2²+3²) = √13
We can also see that the adjacent longer sides are twice this length, each being the hypotenuse of a triangle that is 6 wide and 4 high.
AC = √(6² +4²) = √52 = 2√13
Then the area is ...
A = LW
A = (2√13)(√13) = 2·13 = 26 . . . square units
Answer:
A and D
Step-by-step explanation:
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