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bixtya [17]
2 years ago
9

Which group of measurements is the most precise? (Each group of measurements is for a different object.)

Chemistry
1 answer:
JulijaS [17]2 years ago
3 0

Answer:

rytetrttrrtrt

Explanation:rtyty

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How many mL of 2.0 M KOH are necessary to neutralize 50 mL of 1 M HCl?
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25mL

Explanation:

Please see the step-by-step solution in the picture attached below.

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What factors influence the gravitational forces between objects?
lisabon 2012 [21]

Explanation:

F = k.m1.m2/r²

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k: a constant

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we make 200 mL of a solution with a 0.025 M concentration of Ca(OH)2 The solution is then diluted to 1.00 L by adding additional
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12.00

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3 years ago
The number of energy levels to which an electron can jump depends on the
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The number of energy levels to which an electron can jump depends on the amount of energy the electron possesses. Each energy level has a specific amount of energy an electron needs to have before it can be in there. So, if an electron doesn't have enough energy to be in that energy level then it won't jump to that higher level.
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3 years ago
Read 2 more answers
Astroturf is a durable artificial surface used to cover athletic fields. A soccer field 0.06214- mile-long by 253 ft wide is cov
love history [14]

Answer:

The weight of the Astroturf is 179,684.31 Newtons.

Explanation:

Length of a soccer field = 0.06214 mile = 328.0992 feet

(1 mile = 5280 feet)

Breadth of a soccer field  = 253 feet

Length of a Astroturf which soccer field is to be covered, l = 328.0992 feet

Breadth of a Astroturf which soccer field is to be covered ,b = 253 feet

Thickness of a Astroturf with which soccer field is to be covered = h

h = ½ inch = 0.5 inch = 0.041665 feet

(1 inches = 0.08333 feet)

Volume of the Astroturf ,V= l × b × h

V=328.0992 ft\times 253 ft\times 0.041665 ft=3,458.574 ft^3

Mass of the Astroturf = m

Density of the Astroturf = d = 187 oz/ft^3

d=\frac{m}{V}

m=d\times V= 187 oz/ft^3\times 3,458.574 ft^3=646,753.35 oz

1 oz = 0.0283495 kg

m=646,743.35 oz=646,743.35\times 0.0283495 kg=18,335.13 kg

Weight of the Astroturf = W

W = mg

=W=18,335.13 kg\times 9.8 m/s^2=179,684.31 N

The weight of the Astroturf is 179,684.31 Newtons.

8 0
3 years ago
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