Answer:one gram by 1oC
Explanation: you will need to know the value of water's specific heat
Answer:
The equation is Fe₂O₃ + CO ⇒ Fe + CO₂.
The balanced reaction equation is Fe₂O₃ + 3CO ⇒ 2Fe + 3CO₂.
Explanation:
First, we have to write our equation. It's actually pretty straightforward - first we look for our reactants (looks like it's Fe₂O₃ and CO), then we look for our products (Fe and CO₂). Then, we have to balance it so that both sides have the same number of both element.
Currently, we have the equation Fe₂O₃ + CO ⇒ Fe + CO₂. There are 2 Fe atoms, 4 O atoms, and 1 C atom on the left side. There is 1 Fe atom, 2 O atoms, and 1 C atom on the right side.
First thing we can do is give our Fe on the right side a coefficient of 2. This will make it equivalent to the 2 Fe atoms on the left side:
Fe₂O₃ + CO ⇒ 2Fe + CO₂
Next, we need to make sure that we have the same number of C and O atoms on each side. This takes a little bit of thinking, but what we have to do is give CO a coefficient of 3 and CO₂ a coefficient of 3. This gives us 6 O atoms on the left side (when we include the O₃) and 6 O atoms on the right side (since there are 3 O₂ atoms and 3 times 2 is 6). Here's what that looks like:
Fe₂O₃ + 3CO ⇒ 2Fe + 3CO₂
And that's how I balanced the equation. It can be confusing, but with enough practice, it will get easier and easier. :)
Answer: A volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.
Explanation:
Given: 
= ?, 
= 0.55 M
= 100.0 mL, 
= 2.50 M
Formula used to calculate the volume of KBr is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.
Answer:
Molecular formula is : C₆H₈O₆
Explanation:
40.9 % of C, 4.6 % of H, 54.5 % of O means that in 100 g of ascorbic acid, we have 40.9 g of C, 4.6 g of H and 54.5 g of O.
If 1 mol of ascorbic acid weighs 176 g, let's determine the rules of three to know the grams of each element:
100 g of compound has ___ 40.9 g C __ 4.6 g H ___ 54.5 g O
176 g compound mus have:
(176 . 40.9) / 100 = 72 g of C
(176 . 4.6) / 100 = 8 g of H
(176 . 54.5) / 100 = 96 g of O
If we convert the mass to moles:
72 g . 1 mol / 12 g = 6 C
8 g . 1 mol/ 1g = 8 H
96 g . 1mol / 16 g = 6 O
Molecular formula is : C₆H₈O₆
In conclussion, 1 mol of ascorbic acid has 6 moles of C, 8 moles of H and 6 moles of O
