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Gala2k [10]
3 years ago
10

Many atomic dimensions are expressed in angstroms (A). (1A = 1 x 10-8cm). What is the angstrom equal to in terms of the SI units

nanometer (nm) and picometer (pm)? Report your answers in scientific notation.
Chemistry
1 answer:
Nataly [62]3 years ago
7 0

Answer:

1 Å = 1.0 × 10⁻¹ nm

1 Å = 1.0 × 10² pm

Explanation:

Angstrom is the unit of the length which is equal to one ten-billionth of the metre or 10⁻¹⁰ m. It is represented by the symbol is Å .

Angstrom is not part of SI system of the units, but it is considered as a part of metric system.  

Angstrom is used often in natural sciences as well as technology in order to express the sizes of atoms / molecules, and the lengths of the chemical bonds, etc.

1 Å = 10⁻¹⁰ m

1 nm = 10⁻⁹ m

1 pm = 10⁻¹² m

So,  

1 Å = 1.0 × 10⁻¹ nm

1 Å = 1.0 × 10² pm

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what are the reactants in the first word equation above. magnesium+hydrochloric acid ⇒ magnesium chloride + hydrogen
Alex

Answer:

magnesium+ hydrochloric acid is the reactants

Explanation:

the reactants are always in the left and the products are always in the right by

magnesium+hydrochloric acid ⇒ magnesium chloride + hydrogen

by combining magnesium and hydrochloric acid it produces magnesium chloride and hydrogen.

hope this helps..

6 0
3 years ago
Plz help! The best answer will be marked as brainliest!
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Answer:

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6 0
3 years ago
A particular oral contraceptive contains 0.038 mg of ethinyl estradiol in each pill. The formula of this compound is C20H24O2. H
Ray Of Light [21]

<u>Answer:</u> The number of molecules of ethinyl estradiol present in one pill are 7.71\times 10^{16}

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethinyl estradiol = 0.038 mg = 3.8\times 10^-5}g    (Conversion factor: 1 g = 1000 mg)

Molar mass of ethinyl estradiol (C_{20}H_{24}O_2)=[(20\times 12)+(24\times 1)+(2\times 16)]=296g/mol

Putting values in above equation, we get:

\text{Moles of ethinyl estradiol}=\frac{3.8\times 10^{-5}g}{296g/mol}=1.28\times 10^{-7}mol

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules

So, 1.28\times 10^{-7}mol of ethinyl estradiol will contain = (1.28\times 10^{-7}\times 6.022\times 10^{23})=7.71\times 10^{16} number of molecules

Hence, the number of molecules of ethinyl estradiol present in one pill are 7.71\times 10^{16}

5 0
3 years ago
What is the name for CuSO3? a.carbon (II) sulfate b.copper (II) sulfite c.carbon sulfte d.none of these e.copper (I) sulfate Pre
alexdok [17]

(B) Copper (II) sulfite has the chemical formula CuSO3.

Copper(II) sulfate is the chemical compound CuSO4, although it is also known as blue vitriol, Roman vitriol, the vitriol of copper, and bluestone. Copper sulfate is most frequently found as its pentahydrate, which has the chemical formula CuSO4. 5H2O.

For further information on the chemical name of the compound cu2co3, see its chemical formula. This compound is made up of copper cations (Cu2 ) and carbonate anions (CO3), and as a result is known as copper carbonate and is categorized as a salt.

CuCO is the chemical formula for copper(II) carbonate, also known as cupric carbonate. It is an ionic solid (a salt) that, at room temperature, consists of

To learn more about sulfite please click on below link

brainly.com/question/28985453

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5 0
1 year ago
H2 + CaCl2 --&gt; 2HCl + Ca How many grams of HCl are made when 2.93 g of<br><br> Ca are made?
Sholpan [36]

Answer:

H2 + CaCl2 -> 2HCl + Ca

How many grams of HCl are made when 2.93 g of

Ca are made?

Explanation:

From the given balanced chemical equation, it is clear that:

2mol. of HCl and 1mol. of Ca are produced.

2mol. of HCl weighs --- 73.0g

1mol. of Ca weighs --- 40.0g

Hence,

73.0g of HCl and 40.0g of Ca are produced.

When 2.93g of Ca is produced then, how many grams of HCl will be produced?

=> 2.93g Ca * \frac{73.0g HCl}{40.0g Ca} \\=5.35g HCl

Hence, 5.35g of HCl is formed.

4 0
3 years ago
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