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love history [14]
3 years ago
10

The ___ is the best part of an experiment that is not being tested and it used for comparison

Chemistry
2 answers:
Anettt [7]3 years ago
5 0
The answer is control 








aleksandr82 [10.1K]3 years ago
3 0
The control is the part of an experiment that is not being tested and it is used for comparison. 
The control is the best way for us to understand how the variables effect our experiments. 
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What are the atomic and mass numbers for the periodic table of elements
chubhunter [2.5K]

there you go, hope that helps

8 0
3 years ago
A 1.775g sample mixture of potassium hydrogen carbonate is decomposed by heating. if the mass loss is 0.275g what is the percent
Marina86 [1]

A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.

<h3>What is a decomposition reaction?</h3>

A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.

  • Step 1: Write the balanced equation for the decomposition of KHCO₃.

2 KHCO₃(s) → K₂CO₃(s) + CO₂(g) + H₂O(l)

The mass loss of 0.275 g is due to the gaseous CO₂ that escapes the sample.

  • Step 2: Calculate the mass of KHCO₃ that formed 0.275 g of CO₂.

In the balanced equation, the mass ratio of KHCO₃ to CO₂ is 200.24:44.01.

0.275 g CO₂ × 200.24 g KHCO₃/44.01 g CO₂ = 1.25 g KHCO₃

  • Step 3: Calculate the mass percentage of KHCO₃ in the sample.

There are 1.25 g of KHCO₃ in the 1.775 g sample.

%KHCO₃ = 1.25 g/1.775 g × 100% = 70.4%

A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.

Learn more about decomposition reactions here: brainly.com/question/14219426

7 0
2 years ago
liquid octane(CH3)(CH2)6CH3) reacts with gaseous oxygen gas(O2) to produce gaseous carbon dioxide(CO2) and gaseous water(H2O). I
max2010maxim [7]

The percent yield of carbon dioxide will be 49.0 %.

<h3>Percent yield</h3>

First, let's look at the equation of the reaction:

2C_8H_1_8 + 25O_2 -- > 16CO_2 + 18H_2O

The mole ratio of octane to oxygen is 2:25.

Mole of 3.43 g octane = 3.43/114.23 = 0.03 mol

Mole of 19.1 g oxygen = 19.1/32 = 0.60 mol

Thus, octane is limiting.

Mole ratio of octane to carbon dioxide = 2:16.

Equivalent mole of carbon dioxide = 0.03 x 8 = 0.24 mol

Mass of 0.24 mol carbon dioxide = 0.24 x 44.01 = 10.5624 grams

Percent yield of carbon dioxide = 5.18/10.5624 = 49.0 %

More on percent yield can be found here: brainly.com/question/17042787

#SPJ1

6 0
2 years ago
During a solar flare, it is most likely that
ludmilkaskok [199]

Answer:

During a solar flare, the built up magnetic energy n the solar atmosphere is released at once. If a strong solar flare hits the earth, it is most possible that it will destroy the electronics. It is not expected to effect any human beings unless they are travelling towards the outer space are living at higher altitudes.

It can lead to skin can in case of extreme exposures.

I hope the answer is helpful.

Thanks for answering.

6 0
3 years ago
Read 2 more answers
Question 4 (1 point)<br> If you have exactly one million atoms how many moles do you have?
rjkz [21]

Answer:

                       1.66 × 10⁻¹⁸  Moles

Explanation:

                     As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Atoms and Avogadro's Number is given as,

             Number of Moles  =  Number of Atoms ÷ 6.022 × 10²³ Atoms/mol

Putting values,

              Number of Moles  =  1.0 × 10⁶ Atoms ÷ 6.022 × 10²³ Atoms/mol

              Number of Moles  =  1.66 × 10⁻¹⁸  Moles

7 0
4 years ago
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