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wlad13 [49]
3 years ago
15

Select the best single answer. Which of the following accurately lists compounds in order of increasing solubility in water? LiC

l, Br2, O2, methanol (CH3OH) methanol (CH3OH), LiCl, O2, Br2 O2, Br2, LiCl, methanol (CH3OH) LiCl, methanol (CH3OH), Br2, O2
Chemistry
1 answer:
Ann [662]3 years ago
4 0

Answer:

The Correct increasing order of solubility is O2 < Br2 < LiCl < Methanol (CH3OH)

Explanation:

Solubility of compounds or molecules are solely dependent on its inter molecular forces or bonding present in them.

Molecules with Hydrogen bonding usually very soluble in water. Ionic compounds are also very soluble in water because they form ions in solutions. Molecules that possess van der waal forces are usually insoluble in water because they are non-polar.

  • O2 (oxygen gas) and Br2 (bromine gas) have van der waal forces in them. Van der waal forces are stronger in Br2 (bromine gas) than O2 (oxygen gas) because Br2 has more number of electrons.
  • LiCl is ionic in nature which makes it dissolve in water readily. it easily forms its ions (Li+ and Cl- ) in solutions.
  • Methanol (CH3OH) has the highest solubility in water compared to LiCl, Br2 and O2 because it contains Hydrogen bonding which is strongest of all inter molecular forces.  

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Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2
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Answer:

\boxed{28.81}

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:      58.12                   44.01

           2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

m/g:     9.511

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\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}

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