1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
telo118 [61]
3 years ago
10

A golfer hits a golf ball at an angle of 30 degrees from the ground, with an initial velocity of 120 ft/sec. It lands on the gro

und, after 5 seconds
How far did the golf ball travel horizontally?
Physics
1 answer:
Gelneren [198K]3 years ago
8 0
Data:

Vo = 120 ft / s

α = 30°

t = 5 s

x = ?

Formulas:

cos(α) = Vo,x / Vo => Vo,x = Vo * cos(α)

x = Vo,x * t

Calculations:

Vo,x = 120 ft / s * cos(30) = 103.92 ft /s

x = 103.92 ft/s * 5 s = 519.6 ft

Answer: 519.6 ft
You might be interested in
An assumption of learning curve theory is _________
nalin [4]

Answer:

Unit time will decrease

Explanation:

6 0
3 years ago
2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or
krek1111 [17]

a) The work done by the tree is -1.44\cdot 10^5 J

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

W=Fd

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

W=-1.44\cdot 10^5 J is the work done

d=50.0 cm = 0.50 m is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0
3 years ago
A uniform magnetic field passes through a horizontal circular wire loop at an angle 19.5 ∘ from the vertical. The magnitude of t
nlexa [21]

To solve this problem, we will apply the concepts related to Faraday's law that describes the behavior of the emf induced in the loop. Remember that this can be expressed as the product between the number of loops and the variation of the magnetic flux per unit of time. At the same time the magnetic flux through a loop of cross sectional area is,

\Phi = BA Cos \theta

Here,

\theta = Angle between areal vector and magnetic field direction.

According to Faraday's law, induced emf in the loop is,

\epsilon= -N \frac{d\Phi }{dt}

\epsilon = -N \frac{(BAcos\theta)}{dt}

\epsilon = -NAcos\theta \frac{dB}{dt}

\epsilon = -N\pi r^2 cos\theta \frac{d}{dt} ( ( 3.75 T ) + ( 3.05T/s ) t + ( -6.95 T/s^2 ) t^2)

\epsilon = -N\pi r^2 cos\theta( (3.05T/s)-(13.9T/s)t )

At time t = 5.71s,  Induced emf is,

\epsilon = -(1) \pi (0.220m)^2 cos(19.5\°)(  (3.05T/s)-(13.9T/s)(5.71s))

\epsilon = 10.9V

Therefore the magnitude of the induced emf is 10.9V

4 0
3 years ago
Read 2 more answers
Prisms separate <br> light, such as that from the Sun, by wavelength
SVETLANKA909090 [29]
Sorry I'm so late, but I just took this test and the answer is white (for people who didn't study well ;) )
6 0
3 years ago
If two children, with masses of 16 kg and 25 kg, sit in seats opposite one another in a rotating merry-go-round with an arm leng
Jlenok [28]

Answer:

92.25 kgm^2

Explanation:

Assume both children bodies are point particles. The total moment of inertia about the rotation axis of 2 points particles of mass 16 kg and 25 kg at 1.5 m arm length is

\sum I = m_1r_1^2 + m_2r_2^2

where m_1 = 16 kg, m_2 = 25 kg are the masses of 2 children r_1 = R-2 = 1.5m are their distance to the center of rotation

\sum I = 16*1.5^2 + 25*1.5^2 = 1.5^2(16 + 25) = 92.25 kgm^2

4 0
3 years ago
Other questions:
  • What happens when an experiment with new information or new technology produces results that support an existing theory?
    7·2 answers
  • A distance of 2.00 mm separates two objects of equal mass. If it gravitational force between them is 0.0104 N, find the mass of
    8·1 answer
  • Three identical metal spheres are on insulating stands. Sphere A is given an initial charge of q. Sphere A is then briefly touch
    15·1 answer
  • The compound PCl5 decomposes into Cl2 and PCl3. The equilibrium of PCl5(g) Cl2(g) + PCl3(g) has a Keq of 2.24 x 10-2 at 327°C. W
    5·2 answers
  • what is required to bring about a phase change 1.an increase or decrease in pressure 2.an increase or decrease in energy 3.an in
    10·2 answers
  • certification programs are available at all of the following except A. online schools B. vocational school C. community colleges
    8·2 answers
  • How does a television have a negative effect on the environment
    15·1 answer
  • 7.
    10·2 answers
  • Electromagnetic waves can travel through empty space true or false
    8·1 answer
  • Ang larong syato ay isang uri ng larong target games​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!