<em>The answer you are looking for is: </em>
<em><u>True</u>
Hope that helps!! </em>
<em>Have a wonderful day!! </em>
<em>If you ever need anything feel free to ask me!!</em>
The sphere has a constant potential. It is the electric field.
![E = V_{0} = 0](https://tex.z-dn.net/?f=E%20%3D%20V_%7B0%7D%20%3D%200)
In the sphere, then
![E_{x} = 0, E_{y}=0, E_{z}=0](https://tex.z-dn.net/?f=E_%7Bx%7D%20%3D%200%2C%20%20E_%7By%7D%3D0%2C%20%20%20E_%7Bz%7D%3D0)
Outside the sphere, then
![V = V_{0} - E_{0}z + \frac{E_{0}a^{3}z}{(x^{2} +y^{2} + z^{2})^{3/2} }](https://tex.z-dn.net/?f=V%20%3D%20V_%7B0%7D%20-%20E_%7B0%7Dz%20%2B%20%5Cfrac%7BE_%7B0%7Da%5E%7B3%7Dz%7D%7B%28x%5E%7B2%7D%20%2By%5E%7B2%7D%20%2B%20z%5E%7B2%7D%29%5E%7B3%2F2%7D%20%20%20%7D)
The elements of the electric field include
![E_{x} =\frac{3E_{0}a^{3}xy}{(x^{2} +y^{2} +z^{2})^{5/2}}\\E_{y} = \frac{3E_{0}a^{3}xz}{(x^{2} +y^{2}+z^{2})^{5/2}}](https://tex.z-dn.net/?f=E_%7Bx%7D%20%3D%5Cfrac%7B3E_%7B0%7Da%5E%7B3%7Dxy%7D%7B%28x%5E%7B2%7D%20%2By%5E%7B2%7D%20%2Bz%5E%7B2%7D%29%5E%7B5%2F2%7D%7D%5C%5CE_%7By%7D%20%3D%20%5Cfrac%7B3E_%7B0%7Da%5E%7B3%7Dxz%7D%7B%28x%5E%7B2%7D%20%2By%5E%7B2%7D%2Bz%5E%7B2%7D%29%5E%7B5%2F2%7D%7D)
Which becomes,
![=E_{0} (1-\frac{a^{3}}{x^{2} +y^{2}+z^{2})^{3/2}}+\frac{3a^{3}z^{2}}{(x^{2} +y^{2}+z^{2})^{5/2}})](https://tex.z-dn.net/?f=%3DE_%7B0%7D%20%281-%5Cfrac%7Ba%5E%7B3%7D%7D%7Bx%5E%7B2%7D%20%2By%5E%7B2%7D%2Bz%5E%7B2%7D%29%5E%7B3%2F2%7D%7D%2B%5Cfrac%7B3a%5E%7B3%7Dz%5E%7B2%7D%7D%7B%28x%5E%7B2%7D%20%2By%5E%7B2%7D%2Bz%5E%7B2%7D%29%5E%7B5%2F2%7D%7D%29)
<h3>
In a consistent electric field, is force constant?</h3>
Similar to an ordinary object in the uniform gravitational field near the Earth's surface, a charged item in a uniform electric field experiences a constant force and consequently experiences a uniform acceleration. The vector cross product of p and E determines the torque's direction.
If the charge is positive, the force either moves in the same direction as E or in the opposite direction (if charge is negative).
A torque is experienced by an electric dipole (p) in an even electric field (E). The vector cross product of p and E determines the torque's direction.
To learn more about uniform electric field, visit
brainly.com/question/17426130
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Answer:
. The loop is pushed to the right, away from the magnetic field
Explanation
This decrease in magnetic strength causes an opposing force that pushes the loop away from the field
Answer:
9 cm
-36 cm
Explanation:
u = Object distance
v = Image distance
f = Focal length = 12
m = Magnification = 4
![m=-\frac{v}{u}\\\Rightarrow 4=-\frac{v}{u}\\\Rightarrow v=-4u](https://tex.z-dn.net/?f=m%3D-%5Cfrac%7Bv%7D%7Bu%7D%5C%5C%5CRightarrow%204%3D-%5Cfrac%7Bv%7D%7Bu%7D%5C%5C%5CRightarrow%20v%3D-4u)
Lens equation
![\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{12}=\frac{1}{u}+\frac{1}{-4u}\\\Rightarrow \frac{1}{12}=\frac{3}{4u}\\\Rightarrow u=9\ cm](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%3D%5Cfrac%7B1%7D%7Bu%7D%2B%5Cfrac%7B1%7D%7Bv%7D%5C%5C%5CRightarrow%20%5Cfrac%7B1%7D%7B12%7D%3D%5Cfrac%7B1%7D%7Bu%7D%2B%5Cfrac%7B1%7D%7B-4u%7D%5C%5C%5CRightarrow%20%5Cfrac%7B1%7D%7B12%7D%3D%5Cfrac%7B3%7D%7B4u%7D%5C%5C%5CRightarrow%20u%3D9%5C%20cm)
Object distance is 9 cm
![v=-4\times 9=-36\ cm](https://tex.z-dn.net/?f=v%3D-4%5Ctimes%209%3D-36%5C%20cm)
Image distance is -36 cm (other side of object)