Answer:
0.167m/s
Explanation:
According to law of conservation of momentum which States that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision. The bodies move with a common velocity after collision.
Given momentum = Maas × velocity.
Momentum of glider A = 1kg×1m/s
Momentum of glider = 1kgm/s
Momentum of glider B = 5kg × 0m/s
The initial velocity of glider B is zero since it is at rest.
Momentum of glider B = 0kgm/s
Momentum of the bodies after collision = (mA+mB)v where;
mA and mB are the masses of the gliders
v is their common velocity after collision.
Momentum = (1+5)v
Momentum after collision = 6v
According to the law of conservation of momentum;
1kgm/s + 0kgm/s = 6v
1 =6v
V =1/6m/s
Their speed after collision will be 0.167m/s
Answer: I maybe wrong but i'm pretty sure its C) Kinetic energy
Answer:
Part a)
A = 0.066 m
Part b)
maximum speed = 0.58 m/s
Explanation:
As we know that angular frequency of spring block system is given as
here we know
m = 3.5 kg
k = 270 N/m
now we have
Part a)
Speed of SHM at distance x = 0.020 m from its equilibrium position is given as
Part b)
Maximum speed of SHM at its mean position is given as
A because centrifugal is to velocity to how slow or fast something is and centrifugal has expresssed as ac=v2 / r (1)<span />
Metal
Explanation:
semiconductors are materials which have a conductivity between conductors (generally metals)
