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3 years ago

Which choice is characterized by being malleable? A. metaloids B. metals C. noble gases D. nonmetals

Chemistry

2 answers:

Ainat [17]3 years ago

4 0

The correct answer is metals

amid [387]3 years ago

4 0

Answer: option B. metals.

Justification:

1) Elements can be classified into three main categories: metals, nonmetals, and metaloids.

The metals constitute the most of the elements, which you can see in a periodic table.

2) Most metals are ductiles and malleables, which means that they can be formed into thin sheets and wires.

3) The nonmetals are either gases or brittle solids, ergo they are not malleables.

4) Metalloids have some metallic properties, son nonmetallic properties, and some intermediate properties. They are not malleable nor ductile. There are only 8 metalloids: boron, silicon, germanium, arsenic, antimony, tellurium, polonium and astatine. They are brittle.

The malleabillity is a typical property of the metals.

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Shalnov [3]

Answer: Most people think positively about chemistry. Chemistry has had a good impact on the world, such as the impact of renewable energy, clean water, and technology.

Explanation:

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2 years ago

Calculate the mass in grams in nine molecules of CH3COOH? Please show how you got your answer.

WINSTONCH [101]

M CH₃COOH: 12u×2 + 1u×4 + 16u×2 = 60u

m 9CH₃COOH: 60u×9 = 540u

(1u ≈ 1,66·10⁻²⁴g)
-----------------------------
1u ------- 1,66·10⁻²⁴g
540u ---- X
X = 540×1,66·10⁻²⁴g
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3 years ago

URGENT is... Mg(ClO3)2

stiv31 [10]

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3 years ago

Read 2 more answers

You determine that Lauren's EER is 2200 kcal/day. You recommend and intake of 60% CHO, 15% protein, and 25% fat. Approximately h

const2013 [10]

Answer:

The answer to your question is 330 g of CHO

Explanation:

Data

Calories needed = 2200 kcal/day

CHO = 60%

Proteins = 15%

Fats = 25%

Grams of carbohydrates needed = ?

Process

1.- Calculate the number of calories in 60% of 2200 kcal

2200 kcal ---------------- 100%

x --------------- 60%

x = (60 x 2200) / 100

x = 1320 kcal

2.- Calculate the grams of CHO

1 g of CHO ---------------- 4 kcal

x ---------------- 1320 kcal

x = (1320 x 1) / 4

x = 1320/4

x = 330 g of CHO

6 0

2 years ago

The initial pressure of a mixture of C6H6 and an excess of H2 in a rigid vessel is 1.21 atm. A catalyst is introduced. After the

KengaRu [80]

Answer:

mole fraction of C6H6 = 0.613 atm

Explanation:

The equation for this reaction is :

$C_6H_6 _{(g)} + 3H_2_{(g)} \to C_6H_{12}_{(g)}$

Initial P₁ P₂ 0

Final 0 P₂ -P₁/2 P₁

After completion of the reaction;

P₁ + P₂ = 1.21 atm ----- (1)

P₂ - P₁/2 + P₁ = 0.839 atm

P₂ + P₁/2 = 0.839 atm ----- (2)

Subtracting (2) from (1); we have:

P₁/2 = 0.371

P₁ = 0.742 atm

From(1)

P₁ + P₂ = 1.21 atm

0.742 atm + P₂ = 1.21 atm

P₂ = 1.21 atm - 0.742 atm

P₂ = 0.468 atm

Thus, the partial pressure of C6H6 = 0.742 atm

∴

Partial pressure = Total pressure × mole fraction of C6H6

mole fraction of C6H6 = Partial pressure / Total pressure

mole fraction of C6H6 = 0.742 atm / 1.21 atm

mole fraction of C6H6 = 0.613 atm

5 0

3 years ago