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4 years ago

Which choice is characterized by being malleable? A. metaloids B. metals C. noble gases D. nonmetals

Chemistry

2 answers:

Ainat [17]4 years ago

4 0

The correct answer is metals

amid [387]4 years ago

4 0

Answer: option B. metals.

Justification:

1) Elements can be classified into three main categories: metals, nonmetals, and metaloids.

The metals constitute the most of the elements, which you can see in a periodic table.

2) Most metals are ductiles and malleables, which means that they can be formed into thin sheets and wires.

3) The nonmetals are either gases or brittle solids, ergo they are not malleables.

4) Metalloids have some metallic properties, son nonmetallic properties, and some intermediate properties. They are not malleable nor ductile. There are only 8 metalloids: boron, silicon, germanium, arsenic, antimony, tellurium, polonium and astatine. They are brittle.

The malleabillity is a typical property of the metals.

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Why is boiling water a physical change

Harrizon [31]

Answer:

Boiling water is an example of a physical change and not a chemical change because the water vapor still has the same molecular structure as liquid water (H2O).

Explanation:

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3 years ago

which nonmetals could form an ionic compound with the formula MgX^2 ( where X represents the nonmetal)? (possible, not possible)

djverab [1.8K]

Answer:

The answer to your question is:

Explanation:

Ionic compound is formed when a metal and a nonmetal are attached.

If we have MgX₂, that means that the nonmetal must have a valence of -1.

From the list the nonmetals with a valence of -1 are:

Bromine(Br) and fluorine(F).

7 0

4 years ago

Please help! Willing to offer Brainliest. :D

Luda [366]

Answer:

The correct answer is beta decay

Explanation:

When a beta particle is emitted from a radioactive atom,at that time the daughter atom that is produced have atomic mass 1 unit more than that of its parental atom.

In the given reaction a beta particle is emitted from the carbon atom resulting in the formation nitrogen atom,The atomic mass of nitrogen atom is 7dalton which is one unit more than the atomic mass of carbon that is 6 dalton.

4 0

3 years ago

In a chemical reaction, the difference between the potential energy of the products and the potential energy of the reactants is

vova2212 [387]

Answer:

4. the heat of reaction

5 0

3 years ago

A sample consisting of 1.0 mol of perfect gas molecules with CV = 20.8 J K−1 is initially at 4.25 atm and 300 K. It undergoes re

Marat540 [252]

Answer : The value of final volume, temperature and the work done is, 8.47 L, 258 K and -873.6 J

Explanation :

First we have to calculate the value of $\gamma$ .

$\gamma=\frac{C_p}{C_v}$

As, $C_p=R+C_v$

So, $\gamma=\frac{R+C_v}{C_v}$

Given :

$C_v=20.8J/K\\\\R=8.314J/K$

$\gamma=\frac{8.314+20.8}{20.8}=1.4$

Now we have to calculate the initial volume of gas.

Formula used :

$P_1V_1=nRT_1$

where,

$P_1$ = initial pressure of gas = 4.25 atm

$V_1$ = initial volume of gas = ?

$T_1$ = initial temperature of gas = 300 K

n = number of moles of gas = 1.0 mol

R = gas constant = 0.0821 L.atm/mol.K

$(4.25atm)\times V_1=(1.0mol)\times (0.0821L.atm/mol.K)\times (300K)$

$V_1=5.80L$

Now we have to calculate the final volume of gas by using reversible adiabatic expansion.

$P_1V_1^{\gamma}=P_2V_2^{\gamma}$

where,

$P_1$ = initial pressure of gas = 4.25 atm

$P_2$ = final pressure of gas = 2.50 atm

$V_1$ = initial volume of gas = 5.80 L

$V_2$ = final volume of gas = ?

$\gamma$ = 1.4

Now put all the given values in above formula, we get:

$(4.25atm)\times (5.80L)^{1.4}=(2.50atm)\times V_2^{1.4}$

$V_2=8.47L$

Now we have to calculate the final temperature of gas.

Formula used :

$P_2V_2=nRT_2$

where,

$P_2$ = final pressure of gas = 2.50 atm

$V_2$ = final volume of gas = 8.47 L

$T_2$ = final temperature of gas = ?

n = number of moles of gas = 1.0 mol

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in above formula, we get:

$(2.50atm)\times (8.47L)=(1.0mol)\times (0.0821L.atm/mol.K)\times T_2$

$T_2=257.9K\approx 258K$

Now we have to calculate the work done.

$w=nC_v(T_2-T_1)$

where,

w = work done = ?

n = number of moles of gas =1.0 mol

$T_1$ = initial temperature of gas = 300 K

$T_2$ = final temperature of gas = 258 K

$C_v=20.8J/K$

Now put all the given values in above formula, we get:

$w=(1.0mol)\times (20.8J/K)\times (258-300)K$

$w=-873.6J$

Therefore, the value of final volume, temperature and the work done is, 8.47 L, 258 K and -873.6 J

8 0

3 years ago