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denis23 [38]
3 years ago
14

Question 1. Count Sergei Lvovich Levitsky invented which of the following? A) Collodion processB) Digital imaging C) Dry plates.

D) Bellows camera. Question 2. What substance was the first photograph made from? A) Bitumen B) Silver.C) Lemon juice.D) Acidic acid. Question 3. The first commercially available digital camera was which of the following? A) Kodak DCS 100 B) Kodak Brownie C) Leica 1000 D) None of the above.
Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0
1. <span>Count Sergei Lvovich Levitsky invented the Bellows camera. The correct option among all the options that are given in the question is the last option or option "D".

2. The substance with which the first photograph was made from,  was Bitumen. The correct option among all the options given in the question is the first option or option "A".

3. Kodak DCS 100 was the first commercially available digital camera. The correct option among all the options that are given in the question is the first option or option "A".</span>
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ziro4ka [17]
I believe that the answer is A, continental-continental.
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When the concentration of A in the reaction A ..... B was changed from 1.20 M to 0.60 M, the half-life increased from 2.0 min to
Reika [66]

Answer:

2

0.4167\ \text{M}^{-1}\text{min}^{-1}

Explanation:

Half-life

{t_{1/2}}A=2\ \text{min}

{t_{1/2}}B=4\ \text{min}

Concentration

{[A]_0}_A=1.2\ \text{M}

{[A]_0}_B=0.6\ \text{M}

We have the relation

t_{1/2}\propto \dfrac{1}{[A]_0^{n-1}}

So

\dfrac{{t_{1/2}}_A}{{t_{1/2}}_B}=\left(\dfrac{{[A]_0}_B}{{[A]_0}_A}\right)^{n-1}\\\Rightarrow \dfrac{2}{4}=\left(\dfrac{0.6}{1.2}\right)^{n-1}\\\Rightarrow \dfrac{1}{2}=\left(\dfrac{1}{2}\right)^{n-1}

Comparing the exponents we get

1=n-1\\\Rightarrow n=2

The order of the reaction is 2.

t_{1/2}=\dfrac{1}{k[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{t_{1/2}[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{2\times 1.2^{2-1}}\\\Rightarrow k=0.4167\ \text{M}^{-1}\text{min}^{-1}

The rate constant is 0.4167\ \text{M}^{-1}\text{min}^{-1}

3 0
2 years ago
Which of the following is the correct name for the compound HF? Hydrogen floride hydrogen monofloride Hydroflorous acid Hydroflo
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What is the electron configuration for sulfur? A. 1s2 2s2 2p6 3s2 3p4 B. 1s2 1p6 2s2 2p6 3s2 C. 1s2 2s2 2p6 3s2 3p3 4s1 D. 1s2 2
3241004551 [841]
Sulfur has two filled energy levels and six electrons on the third energy level. The corresponding electron configuration is A.
B is incorrect because there are no p orbitals at the first energy level, ie, no 1p orbitals. C is incorrect because the 4s1 electron would spontaneously drop into the 3p orbitals. D is incorrect because the 3d electrons would spontaneously drop into the 3p orbitals.
3 0
2 years ago
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A chemist must dilute 47.2 mL of 150. mM aqueous sodium nitrate solution until the concentration falls to . He'll do this by add
erma4kov [3.2K]

Answer:

0.295 L

Explanation:

It seems your question lacks the final concentration value. But an internet search tells me this might be the complete question:

" A chemist must dilute 47.2 mL of 150. mM aqueous sodium nitrate solution until the concentration falls to 24.0 mM. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits. "

Keep in mind that if your value is different, the answer will be different as well. However the methodology will remain the same.

To solve this problem we can<u> use the formula</u> C₁V₁=C₂V₂

Where the subscript 1 refers to the concentrated solution and the subscript 2 to the diluted one.

  • 47.2 mL * 150 mM = 24.0 mM * V₂
  • V₂ = 295 mL

And <u>converting into L </u>becomes:

  • 295 mL * \frac{1 L}{1000mL} = 0.295 L

6 0
3 years ago
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