Which set is an example of an element, a compound, and a mixture?

Chemistry

1 answer:

Nitella [24]2 years ago

4 0

Answer:

Element: Sulfur ; S

Compound: Water ; H2O

Mixture: Gunpowder ; 2 KNO3 + S + 3 C -> K2S + N2 + 3 CO2

Explanation:

An element is a pure substance that cannot be broken down into simpler substances. A periodic table for example has elements.

A compound is a chemical substance that's made of multiple elements held together by chemical bonds. All elements from the periodic table can be combined to make a compound but they have to bond a specific way in order for them to actually make something. Water is the easiest to remember.

A mixture is two or more substances that are physically combined. They are not chemically combined though. There are a few types of mixtures including homogeneous, heterogeneous, etc. Gunpowder is actually a mixture. It contains sulfur, carbon and potassium nitrate.

Don't be afraid to reach out with further questions, I hope this helps!

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When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas write the balanved equati

babunello [35]

Answer: When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is $MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$ .

Explanation:

The word equation is given as maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas.

Now, in terms of chemical formulae this reaction equation will be as follows.

$MnO_{2} + HCl \rightarrow H_{2}O + MnCl_{2} + Cl_{2}$

Here, number of atoms on reactant side are as follows.

Mn = 1
O = 2
H = 1
Cl = 1

Number of atoms on product side are as follows.

Mn = 1
O = 1
H = 2
Cl = 4

To balance this equation, multiply HCl by 4 on reactant side and multiply $H_{2}O$ by 2 on product side. Therefore, the equation can be rewritten as follows.

$MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$

Hence, number of atoms on reactant side are as follows.

Mn = 1
O = 2
H = 4
Cl = 4

Number of atoms on product side are as follows.

Mn = 1
O = 2
H = 4
Cl = 4

Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.

Thus, we can conclude that when maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is $MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$ .

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3 years ago

Explain how the ability of dilute sulphuric (vi) acid to conduct an electric current compares with that of concentrated sulphuri

Brut [27]

Answer:

Explanation:

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2 years ago

How many milliliters of a 3.0 M HCL solution are required to make 250.0 milliliters of 1.2 M HCL

tiny-mole [99]

You can use M x V = M' x V'

3 x V = 250 x 1.2

V = 100 ml