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3 years ago

Which is the correct description of the Sun's orbit within the Milky Way Galaxy?

Physics

1 answer:

saveliy_v [14]3 years ago

7 0

Answer:

b .at the outer edge of the Galactic Disk

Explanation:

The sun is located on the outeredge of the galaxy. So it has an orbit within our Milky Way galaxy that is also located arround the outer edge of the galactic disk, and goes around in about 30 million years.

In reallity, allong its trayectory, the sun goes above and below the gallactic disk, but it stays in the outer edge of the galaxy, far away from the galactic bulge and the galactic center, but closer to it than the galactic halo.

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Describe the relationship of attractive forces between molecules

Ede4ka [16]

Describe the relationship of attractive forces between molecules and the ability of a solvent to dissolve a substance. Solvents can dissolve a substance only if the attraction of the solvent molecules is greater than the attraction between the molecules of the substance.

4 0

3 years ago

Vlad1618 [11]

Answer:

a) 16m/s b) 192m

Explanation:

v1=32m/s a=-2m/s^2 t=8s v2=? d=??

a) I will use this equation v2= v1 + a*t

v2= 32m/s + -2m/s^2 * 8s

v2= 32m/s + -16m/s

v2= 16m/s

b) v2^2=v1^2 + 2ad

rearranging

v2^2-v1^2=2ad

v2^2-v1^2/2= a d

v2^2-v1^2/2a=d

16m/s^2 - 32m/s^2/ 2 x-2m/s^2 =d

d=192m

5 0

2 years ago

If a tomato is considered a fruit... then is ketchup considered a smoothie?

Anna71 [15]

Answer:

depends... do you add suger to your ketchup?

Explanation:

8 0

3 years ago

Calculate the drop voltage for a battery of internal resistance 2 ohm and emf of 24 volt

Ivenika [448]

Answer:

The drop voltage is 0.3 V

Explanation:

Electromotive Force EMF

When connecting a battery of internal resistance Ri and EMF ε to an external resistance Re, the current through the circuit is:

$\displaystyle i=\frac{\varepsilon }{R_e+R_i}$

The battery has an internal resistance of Ro=2 Ω, ε=24 V and is connected to an external resistance of Re=158 Ω. Thus, the current is:

$\displaystyle i=\frac{24 }{158+2}$

$\displaystyle i=\frac{24 }{160}$

i = 0.15 A

The drop voltage is the voltage of the internal resistance:

$V_i = i.R_i$

$V_i = 0.15*2$

$\boxed{V_i = 0.3\ V}$

The drop voltage is 0.3 V

3 0

2 years ago

What is the current if 4C of charge passes in 2 s?

julia-pushkina [17]

Answer:

I hope 2 amperes of current passes

8 0

2 years ago