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Lynna [10]
3 years ago
9

Which is the correct description of the Sun's orbit within the Milky Way Galaxy?

Physics
1 answer:
saveliy_v [14]3 years ago
7 0

Answer:

b .at the outer edge of the Galactic Disk

Explanation:

The sun is located  on the outeredge of the galaxy. So it has an orbit within our Milky Way galaxy that is also located arround the <u>outer edge of the galactic disk</u>, and goes around in about 30 million years.

In reallity, allong its trayectory, the sun  goes above and below the gallactic disk, but it stays in the outer edge of the galaxy, <u>far away from the galactic bulge and the galactic center</u>, but closer to it than the galactic halo.

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Problem 8: Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric fi
yanalaym [24]

Answer:

10581.59 V

Explanation:

We are given that

Magnetic field=B=0.65 T

Speed of electron=v=6.1\times 10^7m/s

Charge on electron, q=e=1.6\times 10^{-19} C

Mass of electron,m_e=9.1\times 10^{-31} kg

We have to find the potential difference in volts required in the first part of the experiment to accelerate electrons.

V=\frac{v^2m_e}{2e}

Where V=Potential difference

m_e=Mass of electron

v=Velocity of electron

Using the formula

V=\frac{(6.1\times 10^7)^2\times 9.1\times 10^{-31}}{2\times 1.6\times 10^{-19}}

V=10581.59 V

Hence, the potential difference=10581.59 V

8 0
3 years ago
Suppose the conducting wire (with resistance R) was replace with one of the same material but has its dimension doubled (the len
sveticcg [70]
Resistance of a wire is directly proportional to its length and inversely proportional to the square of its radius.
Thus, if the length is doubled, and the radius is halved:
R₂ = 2R₁/(1/2)²
R₂ = 8R₁
Therefore the resistance increases eight times.
6 0
3 years ago
What is the name of the gland that wraps around the front part of the throat at the Adam's apple, and that produces hormones tha
Grace [21]
B. Thyroid Gland is the correct answer
4 0
3 years ago
Read 2 more answers
An unmanned spacecraft is in a circular orbit around the moon, observing the lunar surface from an altitude of 43.0 km . To the
GalinKa [24]

Answer: v₂ = 5962 km

the spacecraft  will crash into the lunar surface at a speed of 5962 km if nothing is done to correct its orbits

Explanation:

Given that;

Lunar surface is in an altitude h = 43.0 km =  43 × 10³ m

we know; Radius of moon R₁ = 1.74 × 10⁶, mass of moon = 7.35 × 10²²

speed of the space craft when it crashes into the lunar surface , v

decreasing speed of the space craft = 23 m/s

Now since the space craft travels in a circular orbit, we use centrifugal expression Fe = mv²/r

but the forces is due to gravitational forces between space craft and lunar surface Fg = GMn/r²

HERE r = Rm + h

we substitute

r = 1.74 × 10⁶ m + 43 × 10³ m

= 1.783 × 10⁶ m

On equating these, we have

G is gravitational force ( 6.673 × 10⁻¹¹ Nm²/kg²)

v²/r = GM/r²

v = √ ( GM/r)

v = √ ( 6.673 × 10⁻¹¹ Nm²/kg² × 7.35 × 10²² / 1.783 × 10⁶ )

v = √ (2750787.9978)

v = 1658.55 m/s

Now since speed is decreasing by 23 m/s

the speed of the space craft into the lunar face is,

v₁ = 1658.55 m/s - 23 m/s

v₁ = 1635.55 m/s

Now applying conversation of energy, we say

1/2mv₂² = 1/2mv₁² + GMem (1/Rm - 1/r)

v₂ =  √ [ v₁² + GMe (1/Rm - 1/r)]

v₂ =   √ [ 1635.55²  + ( 6.673 × 10⁻¹¹ Nm²/kg² × 7.35 × 10²²) (1/ 1.74 × 10⁶ - 1 / 1.783 × 10⁶)]

v₂ =  √ (2675023.8025 + 67979.24)

v₂ = √(2743003.046)

v₂ = 1656.2 m/s

now convert

v₂ = 1656.2 × 1km/1000m × 3600s/1hrs

v₂ = 5962 km

Therefore the spacecraft  will crash into the lunar surface at a speed of 5962 km if nothing is done to correct its orbits

8 0
3 years ago
A 500 kg empty elevator moves with a downwards acceleration of 2 m/s2. What is the tension force of the cable on the elevator? 5
Gre4nikov [31]

Answer:

T = 4000 N

Explanation:

We have,

Mass of an elevator, m = 500 kg

It is moving downward with an acceleration of 2\ m/s^2. It is required to find the  tension force of the cable on the elevator. We know that when the elevator is moving downward, the net force on it is given by :

F=m(g-a)

g is acceleration due to gravity

F=500\times (10-2)\\\\F=4000\ N

So, the tension force of the cable on the elevator is 4000 N.

5 0
3 years ago
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