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3 years ago

Which is the correct description of the Sun's orbit within the Milky Way Galaxy?

Physics

1 answer:

saveliy_v [14]3 years ago

7 0

Answer:

b .at the outer edge of the Galactic Disk

Explanation:

The sun is located on the outeredge of the galaxy. So it has an orbit within our Milky Way galaxy that is also located arround the outer edge of the galactic disk, and goes around in about 30 million years.

In reallity, allong its trayectory, the sun goes above and below the gallactic disk, but it stays in the outer edge of the galaxy, far away from the galactic bulge and the galactic center, but closer to it than the galactic halo.

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A pendulum consisting of a 0.5 kg mass tied to a 0.3 m string is set into oscillation at the same moment that a stone is dropped

lara31 [8.8K]

Answer:

2.72 cycles

Explanation:

First of all, let's find the time that the stone takes to reaches the ground. The stone moves by uniform accelerated motion with constant acceleration g=9.8 m/s^2, and it covers a distance of S=44.1 m, so the time taken is

$S=\frac{1}{2}at^2\\t=\sqrt{\frac{2S}{a}}=\sqrt{\frac{2(44.1m)}{9.8 m/s^2}}=3 s$

The period of the pendulum instead is given by:

$T=2 \pi \sqrt{\frac{L}{g}}=2 \pi \sqrt{\frac{0.3 m}{9.8 m/s^2}}=1.10 s$

Therefore, the number of oscillations that the pendulum goes through before the stone hits the ground is given by the time the stone takes to hit the ground divided by the period of the pendulum:

$N=\frac{t}{T}=\frac{3 s}{1.10 s}=2.72$

6 0

3 years ago

on the surface of jupiter the acceleration due to gravity is about 3 times that on earth. how much would a 100kg rock weigh on j

madam [21]

Answer:

Weight on Jupiter will be equal to 2940 N

Explanation:

We have given given acceleration due to gravity on Jupiter is 3 times of acceleration due to gravity on earth

Acceleration due to gravity on earth $g=9.8m/sec^2$

So acceleration due to gravity on Jupiter = $g'=3\times 9.8=29.4m/sec^2$

Mass is given m = 100 kg

We have to find the weight

Weight is equal to W = mg, here m is mass and a is acceleration

So weight $W=100\times 29.4=2940N$

4 0

3 years ago

Read 2 more answers

Detlev walks 1000 meters north to the store and walks back 900 meters south to his friends house. The friends house is 100 meter

lilavasa [31]

1000 is the correct answer

3 0

2 years ago

A 23 g bullet traveling at 230 m/s penetrates a 2.0 kg block of wood and emerges cleanly at 170 m/s. If the block is stationary

Ann [662]

The distance traveled by the wood after the bullet emerges is 0.16 m.

The given parameters;

mass of the bullet, m = 23 g = 0.023 g
speed of the bullet, u = 230 m/s
mass of the wood, m = 2 kg
final speed of the bullet, v = 170 m/s
coefficient of friction, μ = 0.15

The final velocity of the wood after the bullet hits is calculated as follows;

$m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\0.023(230) + 2(0) = 0.023(170) + 2v_2\\\\5.29 = 3.91 + 2v_2\\\\2v_2 = 1.38\\\\v_2 = \frac{1.38}{2} = 0.69 \ m/s$

The acceleration of the wood is calculated as follows;

$\mu = \frac{a}{g} \\\\a = \mu g\\\\a = 0.15 \times 9.8\\\\a = 1.47 \ m/s^2$

The distance traveled by the wood after the bullet emerges is calculated as follows;

$v^2 = v_0^2 + 2as\\\\v^2 = 0 + 2as\\\\v^2 = 2as\\\\s = \frac{v^2}{2a} \\\\s = \frac{(0.69)^2}{2(1.47)} \\\\s = 0.16 \ m$

Thus, the distance traveled by the wood after the bullet emerges is 0.16 m.

Learn more here:brainly.com/question/15244782

7 0

3 years ago

A carpenter on the roof of a building accidentally drops herhammer. As the hammer falls it passes two windows of equal height,a)

nadezda [96]

Answer:

Explanation:

a) the speed increment of the hammer as it drops past the first window, is greater than that of the speed of the hammer as it drops past the second window. This can also be translated as saying that the hammer spent more time at the second window.

b) III

The best answer would be answer III, The hammer spends more time dropping past window 1, which I had already included in my explanation in (a) above.

4 0

2 years ago