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Alex17521 [72]
3 years ago
13

Which computational model can be applied to the total internal energy of a system with two point masses?

Physics
1 answer:
I am Lyosha [343]3 years ago
4 0

Answer:

D

Explanation:

Took the test :)

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A stone is dropped into a river from a bridge at a height h above the water. Another stone is thrown vertically down at a time t
Mumz [18]

Answer:

v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}

Explanation:

We will apply the equations of kinematics to both stones separately.

First stone:

Let us denote the time spent after the second stone is thrown as 'T'.

y - y_0 = v_{y_0}(t+T) + \frac{1}{2}a(t+T)^2\\0 - h = 0 + \frac{1}{2}(-g)(t+T)^2\\(t+T)^2 = \frac{2h}{g}\\T = \sqrt{\frac{2h}{g}}-t

Second stone:

y - y_0 = v_{y_0}T + \frac{1}{2}aT^2\\0 - h = v_{y_0}T -\frac{1}{2}gT^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\sqrt{\frac{2h}{g}} - t)^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\frac{2h}{g} + t^2 - 2t\sqrt{\frac{2h}{g}})\\-h = v_{y_0}\sqrt{\frac{2h}{g}} - v_{y_0}t - h -\frac{g}{2}t^2 + gt\sqrt{\frac{2h}{g}}\\v_{y_0}(\sqrt{\frac{2h}{g}} - t) = \frac{g}{2}t^2 - gt\sqrt{\frac{2h}{g}}\\v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}

6 0
3 years ago
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Click through the images and select the model that best shows how J.J. Thomson envisioned the atom.
Alexandra [31]

Answer:

The first one with the big plus in the middle and negatively charged electrons around.

Explanation:

7 0
3 years ago
If we say that one quantity is directly proportional to another quantity, does this mean that they are equal to each other?
Marina CMI [18]

Answer:

Explanation:

It doesn't mean it equal to each other.  lets say x is directly proportional to y. Here, if something happens to x then, y will do the same thing. for example, if x increases, then y also increases. similarly, if x decreases, then y also decreases. therefore, x is something or lets say it is a major factor that decides the fate of y.

6 0
3 years ago
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If the mass is 22 g and the volume is 11 ml, what is the density of the object
andriy [413]
2 g/mL there’s your answer
8 0
3 years ago
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Metabolic power is the rate at which your body "burns" fuel to power your activities. For many activities, your body is roughly
DerKrebs [107]

Answer:

Metabolic power 420.138 W

Explanation:

Given data:

considering drag coefficient Cd =  0.9

Assuming cross section of cyclist A = 0.50 m^2

Take density of air ρ = 1.2 kg/m3

We know that drag force is given as

Drag\ Force = Cd\times 1/2 \times \rho AV^2


D = 0.9\times 1/2\times 1.2\times 0.5\times 7.3^2


D = 14.388 N

Power = D\times V = 14.388\times 7.3 = 105.03 W

hence metabolic power is given as

Metabolic power = \frac{D}{\eta}

                   = \frac{105.03}{0.25}

                          = 420.138 W

7 0
3 years ago
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