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sveticcg [70]
3 years ago
14

to get a flat uniform cylindrical satellite spinning at the correct rate, scientists fire 4 tangential rockets. suppose that the

satellite has a mass of 3600 kg and a radius of 4m, and that the rockets each add a mass of 250 kg. what is the steady force required of each rocket if the satellite is to reach 32 rpm in 5 min starting from rest.
Physics
1 answer:
Elena-2011 [213]3 years ago
3 0

Answer:

The steady force required of each rocket is 31.36 N

Explanation:

Given that,

Mass of satellite = 3600 Kg

Radius = 4 m

Mass of rocket = 250 kg

Time = 5 min

Angular velocity = 32 rpm

We need to calculate the moment of inertia

Using formula of moment of inertia

I=\dfrac{1}{2}Mr^2+4mr^2

Where, M = mass of satellite

r = radius

m = mass of rocket

Put the value into the formula

I=\dfrac{1}{2}\times3600\times4^2+4\times250\times4^2

I=44800\ kg-m^2

We need to calculate the angular acceleration

Using formula of angular acceleration

\alpha=\dfrac{\omega}{t}

Where, \omega = angular velocity

t = time

Put the value into the formula

\alpha=\dfrac{2\pi\times32}{3600\times5}

\alpha=0.0112\ rad/s^2

We need to calculate the steady force required of each rocket

Using formula of torque

\tau=I\alpha

4rF=I\alpha

F=\dfrac{I\alpha}{4r}

Put the value into the formula

F=\dfrac{44800\times0.0112}{4\times4}

F=31.36\ N

Hence, The steady force required of each rocket is 31.36 N

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12. A flat circular coil of wire having 200 turns and diameter 6.0 cm carries a current of 7.0 A. It is placed in a magnetic fie
IgorLugansk [536]

Answer:

The magnitude of the magnetic torque on the coil is 1.98 A.m²

Explanation:

Magnitude of magnetic torque in a flat circular coil is given as;

τ = NIASinθ

where;

N is the number of turns of the coil

I is the current in the coil

A is the area of the coil

θ is the angle of inclination of the coil and magnetic field

Given'

Number of turns, N = 200

Current, I = 7.0 A

Angle of inclination, θ = 30°

Diameter, d = 6 cm = 0.06 m

A = πd²/4 = π(0.06)²/4  = 0.002828 m²

τ = NIASinθ

τ = 200 x 7 x 0.002828 x Sin30

τ = 1.98 A.m²

Therefore, the magnitude of the magnetic torque on the coil is 1.98 A.m²

4 0
3 years ago
In a nuclear fusion reaction two 2H atoms are combined to produce one 4He.
Mrrafil [7]

Answer:

a)= 0.025602u

b) = 23.848MeV

c) N = 1.546 × 10¹³

Explanation:

The reaction is

²₁H   +   ²₁H   ⇄   ⁴₂H + Q

a) The mass difference is

Δm = 2m(²₁H) - m (⁴₂H)

       = 2(2.014102u) - 4.002602u

        = 0.025602u

b) Use the Einstein mass energy relation ship

The enegy  release is the mass difference times 931.5MeV/U

E = (0.025602) (931.5)

   = 23.848MeV

c)

the number of reaction need per seconds is

N = Q/E

     = 59W/ 23.848MeV

  = \frac{59}{(23.848 \times 10^6 )(1.6 \times 10^1^9) } \\\\= 1.546 \times 10^1^3

N = 1.546 × 10¹³

5 0
3 years ago
A car whose total mass is 800kg travelling with a uniform velocity of 20m/s suddenly observes a stationary dog 50m ahead on its
maxonik [38]

Answer:

The driver hits the stationery dog because the applied force is less than required force

Explanation:

Kinetic energy will be given by

KE=0.5mv^{2} where m is the mass of the vehicle and v is the speed/velocity of the vehicle.

Substituting 800 Kg for m and 20 m/s for v we obtain

KE=0.5*800*(20 m/s)^{2}=160,000

Frictional force by vehicle pads is given by

Fr=\frac {KE}{d} where d is the distance moved

Substituting 160000 for KE and 50 m for d we obtain

Fr=\frac {160000}{50}=3200 N

Therefore, the vehicle hits the dog since the required force is 3200N but the driver applied only 2000 N

7 0
3 years ago
Which units are used to express sound intensity?
grigory [225]

Answer: decibels

Explanation:

4 0
3 years ago
What is the acceleration of an object that goes from 45m/s to 10 m/s in 5 seconds?
kipiarov [429]

Answer:

\boxed {\boxed {\sf a= -7 \ m/s^2}}

Explanation:

Acceleration is the change in velocity over time.

a= \frac {v_f-v_i}{t}

The object accelerates <em>from</em> 45 meters per second <em>to </em>10 meters per second in 5 seconds. Therefore,

v_f=10 \ m/s \\v_i= 45 \ m/s \\t= 5 \ s

Substitute the values into the formula.

a= \frac{ 10 \ m/s - 45 \ m/s}{5 \ s}

Solve the numerator.

a= \frac { -35 \ m/s}{5 \ s}

Divide.

a= -7 \ m/s/s

a= -7 \ m/s^2

The acceleration of the object is -7 meters per square second. The acceleration is negative because the object's velocity decreases and the object slows down.

5 0
3 years ago
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