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sveticcg [70]
3 years ago
14

to get a flat uniform cylindrical satellite spinning at the correct rate, scientists fire 4 tangential rockets. suppose that the

satellite has a mass of 3600 kg and a radius of 4m, and that the rockets each add a mass of 250 kg. what is the steady force required of each rocket if the satellite is to reach 32 rpm in 5 min starting from rest.
Physics
1 answer:
Elena-2011 [213]3 years ago
3 0

Answer:

The steady force required of each rocket is 31.36 N

Explanation:

Given that,

Mass of satellite = 3600 Kg

Radius = 4 m

Mass of rocket = 250 kg

Time = 5 min

Angular velocity = 32 rpm

We need to calculate the moment of inertia

Using formula of moment of inertia

I=\dfrac{1}{2}Mr^2+4mr^2

Where, M = mass of satellite

r = radius

m = mass of rocket

Put the value into the formula

I=\dfrac{1}{2}\times3600\times4^2+4\times250\times4^2

I=44800\ kg-m^2

We need to calculate the angular acceleration

Using formula of angular acceleration

\alpha=\dfrac{\omega}{t}

Where, \omega = angular velocity

t = time

Put the value into the formula

\alpha=\dfrac{2\pi\times32}{3600\times5}

\alpha=0.0112\ rad/s^2

We need to calculate the steady force required of each rocket

Using formula of torque

\tau=I\alpha

4rF=I\alpha

F=\dfrac{I\alpha}{4r}

Put the value into the formula

F=\dfrac{44800\times0.0112}{4\times4}

F=31.36\ N

Hence, The steady force required of each rocket is 31.36 N

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The sun’s___and the planet’s___keeps planets moving is___orbits.
Sauron [17]

The sun’s gravitational attraction and the planet’s inertia keeps planets moving is circular orbits.

Explanation:

The planets in the Solar System move around the Sun in a circular orbit. This motion can be explained as a combination of two effects:

1) The gravitational attraction of the Sun. The Sun exerts a force of gravitational attraction on every planet. This force is directed towards the Sun, and its magnitude is

F=G\frac{Mm}{r^2}

where

G is the gravitational constant

M is the mass of the Sun

m is the mass of the planet

r is the distance between the Sun and the planet

This force acts as centripetal force, continuously "pulling" the planet towards the centre of its circular orbit.

2) The inertia of the planet. In fact, according to Newton's first law, an object in motion at constant velocity will continue moving at its velocity, unless acted upon an external unbalanced force. Therefore, the planet tends to continue its motion in a straight line (tangential to the circular orbit), however it turns in a circle due to the presence of the gravitational attraction of the Sun.

Learn more about gravity:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

8 0
3 years ago
A 6- F capacitor is charged to 90 V and is then connected across a 700- resistor. What is the initial charge on the capacitor
Lorico [155]

Answer:

540C.

Explanation:

A capacitor of capacitance C when charged to a voltage of V will have a charge Q given as follows;

Q = CV          ----------(i)

From the question, the initial charge on the capacitor is the charge on it before it was connected to the resistor. In other words, the initial charge on the capacitor will have a maximum value which can be calculated using equation (i) above.

Where;

C = 6F

V = 90V

Substitute these values into equation (i) as follows;

Q = 6 x 90

Q = 540 C

Therefore, the initial charge on the capacitor is 540C.

7 0
2 years ago
PLEASE HELP!!!!!
Sunny_sXe [5.5K]
I need to force in order to answer. What is it
3 0
2 years ago
A tray of electronic components contains 15 components, 4 of which are defective. If 4 components are selected, what is the poss
dlinn [17]

Answer:

a) 0.0007326

b) 0.03223

c) 0.2418

d) 0.2418

Explanation:

To find different probabilities for the selection of components among eleven good and four defective components, we will use the Combination.

a) C(4,4) = 1; C(15,4) = 1365

P = \frac{C(4,4)}{C(15,4)} = \frac{1}{1365} = 0.0007326

b) C(4,3) = 4; C(11,1) = 11

P = \frac{C(4,3)*C(11,1)}{C(15,4)} = \frac{4*11}{1365} = 0.03223

c) C(4,2) = 6; C(11,2) = 55

P = \frac{C(4,2)*C(11,2)}{C(15,4)} = \frac{6*55}{1365} = 0.2418

d) C(11,4) = 330

P = \frac{C(11,4)}{C(15,4)} = \frac{330}{1365} = 0.2418

8 0
2 years ago
Two water jets are emerging from a vessel at a height of 50 centimeters and 100 centimeters. If their horizontal velocities at t
givi [52]
For t1:

t1 = square root of 2h1 / g = square root of 2 * 0.5 / 9.8 = 0.319 sec

For t2:

t2 = sqaure root of 2h2 / g = square root of 2 * 1.0 / 9.8 = 0.451 sec

Wherein:
t = time(s) for the vertical movement
h= height
g = gravity (using the standard 9.8 m/sec measurement)

d1 = 1*0.319 = 0.319 m
d2 = 0.5 * 0.451 = 0.225 m

Where:

d = hor. distance

ratio = d1:d2
= 0.319 : 0.225
=3.19 : 2.25

The answer is 3.19 : 2.25
8 0
3 years ago
Read 2 more answers
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