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Based on the construction, we can logically deduce that: A. yes; the compass was kept at the same width to create the arcs for points C and D.
<h3>What is a line segment?</h3>A line segment can be defined as the part of a line in a geometric figure such as a triangle, circle, quadrilateral, etc., that is bounded by two (2) distinct points and it typically has a fixed length.
In Geometry, a line segment can be measured by using the following measuring instruments:
- A scale (ruler)
- A divider
- A compass
In Geometry, an arc can be defined as a trajectory that is generally formed when the distance from a given point has a fixed numerical value.
Based on the construction with arcs created above and below the line segment from points A, we can infer and logically deduce that it is true that the compass was kept at the same width to create the arcs for points C and D.
In conclusion, yes, the construction demonstrated how to bisect a line segment correctly by hand.
Read more on arcs here: brainly.com/question/11126174
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Complete Question:
The construction has a given segment AB. Arcs have been created above and below the segment from points A that are equidistant from point A. The compass was kept at the same distance, placed on point B, and two additional arcs were created above and below the segment that intersect with the first arcs created. The intersection of the arcs above the segment created point C. The intersection of the arcs below the segment created point D. A line was drawn from point C to D through the segment.
Does the construction demonstrate how to bisect a segment correctly by hand?
A. Yes; the compass was kept at the same width to create the arcs for points C and D.
B. Yes; a straightedge was used to create segment CD.
C. No; the compass was not kept at the same width to create the arcs for points C and D.
D. No; a straightedge was used to create segment CD.
Answer:
The smallest value of p+q is 11
It happens when p = 6 and q = 5.
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Explanation:
Let's factor 180 in such a way that exactly one factor is a perfect square.
I'll ignore the trivial factor of 1.
Here are the possible factorizations we could go with:
180 = 4*45
180 = 9*20
180 = 36*5
Those factorizations then lead to the following
Then we have
p+q = 2+45 = 47
p+q = 3+20 = 23
p+q = 6+5 = 11
The smallest value of p+q is 11 and it happens when p = 6 and q = 5.
Side note: p+q is smallest when we go with the largest perfect square factor.
Answer: Option C
Step-by-step explanation:
Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:
If then the graph of k(x) will be the graph of f(x) displaced vertically b units down.
If then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.
In this case we have
We know that this function has its vertex in point (0,0).
Then, to move its vertex 7 units down we apply the transformation:
.
Then the function k(x) that will have its vertex 7 units below f(x) is