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We let y equal to the elevation above sea level so that the elevation of the rock climber after x minutes of climbing would be:
y = 2x + 50
His initial height can be calculated when x is equal to zero it is when the climber is not yet climbing. Therefore, the rock climber'sinitial height above sea level would be 50 meters.
Answer:
C
Step-by-step explanation:
a-b-c
-3-4-(-5)
-3-4+5 [as - - = +]
-2
A) 19m because 3 times 6 is 18 then you add m, which would be 19m
For perpendicular lines, m1m2 = -1 or m2 = -1/m1; where m1 and m2 are the slopes of the lines.
Here line 1 is 2x - y - 7 = 0
y = 2x - 7; Hence m1 = 2
m2 = -1/2
Required equation y - y1 = m2(x - x1)
y - (-1) = -1/2(x - 4)
y + 1 = -1/2x + 2
y = -1/2x + 2 - 1
y = -1/2x + 1
