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romanna [79]
3 years ago
7

Barbara is conducting an experiment to observe heat flow. She places one piece of metal in a freezer at -18 degrees Celsius (°C)

and a second piece of metal in an oven at 200 °C. After 2 hours, she takes the metal pieces out of the freezer and oven and places them both in the same beaker of boiling water for two minutes. Which of the following best describes how some of the heat will initially move in this system?
Heat will flow from the frozen metal into the hot metal.


Heat will flow from the boiling water into the hot metal.


Heat will flow from the boiling water into the frozen metal.


Heat will flow from the frozen metal into the boiling water.
Chemistry
1 answer:
yulyashka [42]3 years ago
4 0

<u>Answer:</u> The correct answer is heat will flow from the boiling water into the frozen metal.

<u>Explanation:</u>

According to the law of conservation of energy, energy cannot be destroyed nor created but it can be transformed from 1 form to another form.

There are 3 processes of heat transfer:

  1. <u>Conduction:</u> This type of heat transfer occurs when there is direct contact between the two objects.
  2. <u>Convection:</u> This type of heat transfer occurs when there is a movement of fluid (liquid or gas) due to the movement of hot layers to the top and cold layers to the bottom which leads to convection currents.  
  3. <u>Radiation:</u> This type of heat transfer occurs when there is a direct transfer of energy through space.

The heat moves from a hot surface to a cold surface to maintain equilibrium.

We are given:

A metal is placed in a freezer (cold object) and another metal is placed in an oven (hot object) and then both the metals are placed in boiling water.

Initially, the heat will flow from the boiling water (hot object) into the frozen metal (cold object) to maintain equilibrium

Hence, the correct answer is heat will flow from the boiling water into the frozen metal.

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Which of the following will form a solution? (Select all that apply.)
SSSSS [86.1K]

Answer:

sand and water

Explanation:

when u mix these both it will become like a paste

4 0
2 years ago
A 2.20 mol sample of NO 2 ( g ) is added to a 3.50 L vessel and heated to 500 K. N 2 O 4 ( g ) − ⇀ ↽ − 2 NO 2 ( g ) K c = 0.513
igor_vitrenko [27]

Answer:

[NO₂] = 0.434 M

[N₂O₄] = 0.0971 M

Explanation:

The equilibrum is:  N₂O₄(g)  ⇆  2NO₂ (g)

1 moles of nitrogen (IV) oxide is in equilibrium with 2 moles of nitrogen dioxide.

Initally we only have 2.20 moles of NO₂. So let's write the equilibrium again:

              2NO₂ (g)   ⇆   N₂O₄(g)      

Initially   2.20 mol              -

React          x                      x/2

X amount has reacted, and the half has been formed, according to stoichiometry.

Eq       (2.20-x) / 3.50L     (x/2)/ 3.50L

We divide by the volume because we need molar concentrations. Let's make the Kc's expression:

Kc = [N₂O₄] / [NO₂]²

0.513 = ((x/2)/ 3.50L) /  [(2.20-x) / 3.50L]

0.513 = ((x/2)/ 3.50L) / [(2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / [2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / (4.84 - 4.40x + x²) / 12.25)

0.513 / 12.25 (4.84 - 4.40x + x²) = x/2 / 3.50

0.203 - 0.184x + 0.0419x² = x/2 / 3.50

3.50(0.203 - 0.184x + 0.0419x²) = x/2

7 (0.203 - 0.184x + 0.0419x²) - x = 0

1.421 - 2.288x + 0.2933x² = 0  → Quadratic formula

a = 0.2933 ;  b = -2.288 ; c = 1.421

(-b +- √(b²-4ac)) / (2a)

x₁ = 7.12

x₂ = 0.68 → We consider this value, so we can have a (+) concentration.

Concentrations in the equilibrium are:

[NO₂] = (2.20-0.68) / 3.50 = 0.434 M

[N₂O₄] = (0.68/2) / 3.50  = 0.0971 M

8 0
2 years ago
1) For the following molecules: - Draw the Lewis structures/dots - Determine the polarity (polar or non-polar). - List all inter
4vir4ik [10]

Answer:

ed

Explanation:

ed

8 0
2 years ago
A stone is dropped from the roof of a building; 2.00s after that, a second stone is thrown straight down with an initial speed o
Brut [27]
A) -0.5(9.8)*t^2 = -25(t-2) - 0.5(9.8)(t-2)^2 
-4.9t^2 = -25t + 50 - 4.9(t^2-4t+4) 
0 = -25t+50+19.6t - 19.6 
5.4t = 30.4 
t = 5.62962963 s 

b) h = -4.9(5.62962963)^2 
h = -155.2943759 
the building is 155.2943759 m high 

c) speed 0of first stone 
= at 
= 9.8*5.62962963 
= 55.17037037 m/s 
speed of second stone
= v + at
= 25+9.8*3.62962963 
= 60.57037037 m/s
7 0
3 years ago
The elements in Groups 1A(1) and 7A(17) are all quite reactive. What is a major difference between them?
matrenka [14]

The elements in Groups 1A(1) and 7A(17) are all quite reactive.

<h3>Major difference between Groups 1A(1) and 7A(17) : </h3>

Group 7's halogens, which are non-metal elements, become less reactive as you move down the group. In contrast to the alkali metals in Group 1 of the periodic table, this trend is the opposite. The most reactive element in Group 7 is fluorine.

Alkali metals are soft and reactive metals. They react vigorously with water and become more reactive. And other hand halogens are reactive non metals.

  • Elements of group 1A are known as alkali metals. Elements of this group are lithium, sodium, potassium, rubidium, cesium.
  • Reactivity increase down group 1 but decrease up group 7 this is because group 7 elements react by gaining an electron. As one move down the group, the amount of electron shielding increases, meaning that the electron is less attracted to the nucleus.

To know more about Groups 1A(1) and 7A(17) please click here :

brainly.com/question/13063502

#SPJ4

6 0
1 year ago
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