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Maslowich
3 years ago
12

What is the identity of the element which had the following electron configuration? 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5 ​

Chemistry
1 answer:
kati45 [8]3 years ago
5 0

Answer:

The element with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5 ​ is manganese (25Mn).

Explanation:

Step 1: Data given

The element with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5 ​

has 25 electrons.

This element has 2 electrons on the first shell, 8 electrons on the second shell, 13 electrons on the third shell and 2 electrons on the outer shell (valence electrons).

This means this element is part of group VII.

The element with 25 electrons, we can find on the periodic table, with atomic number 25.

The element with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5 ​ is manganese (25Mn).

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A zinc coating is added to the surface of a tin component to provide corrosion protection to the tin. Assume that the coating ad
Norma-Jean [14]

Answer:

In the presence of salt water and oxygen the coating will not corrode. As long as zinc coating is present and remains intact corrosion is not possible.

Explanation:

Here it is given that a tin is present so firstly tin is made of a chemical element

which belongs to carbon family in periodic table of group 14.

It is a silvery,soft, white metal with a bluish tinge.

Now the covering which is been done on the tin is Zinc.

so, zinc is known to be served as a sacrificial coater.

Their is an amazing reason behind zinc coating being so effective and intact  i.e. Its own corrosive properties are such that it stops corrosion.

Their is a process which is known as a galvanic corrosion which refers to that "ZINC" defers to the metal  to which it is protecting.

It is even more electrochemically active than iron itself.

Here, it is mentioned that zinc coating gets chipped but the coating remains intact. So, if the zinc is not removed from the tin's surface it will not get corroded when it is exposed to salt water and oxygen.

5 0
2 years ago
Prior to hosting an international soccer match, the local soccer club needs to replace the artifical turf on their field with gr
GuDViN [60]

Answer:

It will cost $68,620.5 to the club to add the grass turf to their field.

Explanation:

length of the field = l = 0.102 km = 0.102 × 1000 m

( 1km = 1000 m)

Width of the field w = 0.069 km = 0.069 × 1000 m

Area of the field , A= l × w

A=0.102\times 1000 m\times 0.069\times 1000 m=7,038 m^2

Cost of grass turfing = 9.75 \$/m^2

Cost of grass turfing on field of 7,038 m^2 :

=7,038 m^2\times 9.75 \$/m^2=\$68,620.5

It will cost $68,620.5 to the club to add the grass turf to their field.

4 0
3 years ago
What is the formula of the ionic compound formed by the elements lithium and oxygen?
kozerog [31]
The formula is Letter A) Li2<span>O 

i got 5 out of 5 on this test on plato.</span>
6 0
3 years ago
Read 2 more answers
Will bromine water and magnesium react
bazaltina [42]
No. Magnesium, and Bromine are a chemical compound when put together.
Neither Bromine, nor Magnesium react with any sort of water.
7 0
3 years ago
How many moles of neon atoms are there in a neon sign that has 2.4 * 20^ 24 atoms of neon? *
Whitepunk [10]

Answer:

4 moles of neon

Explanation:

Given data:

Number of moles of neon = ?

Number of atoms of neon = 2.4×10²⁴ atoms

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For given neon atoms:

1 mol =  6.022 × 10²³ atoms

2.4×10²⁴ atoms × 1 mol / 6.022 × 10²³ atoms

0.4×10¹ mol = 4 mol

3 0
3 years ago
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