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Mariulka [41]
3 years ago
9

2ch4(g) c2h2(g) 3h2(g) describe what is happening within the system when it is at equilibrium in terms of concentrations, reacti

ons that occur, and reaction rates.
Chemistry
2 answers:
SashulF [63]3 years ago
4 0

Balanced chemical reaction: 2CH₄(g) ⇄ C₂H₂(g) + 3H₂(g).

1) In a chemical reaction, chemical equilibrium is the state in which both reactants (methane CH₄) and products (ethyne C₂H₂ and hydrogen H₂) are present in concentrations which have no further tendency to change with time.  

2) At equilibrium, both the forward and reverse reactions are still occurring.

3) Reaction rates of the forward and backward reactions are equal and  there are no changes in the concentrations of the reactants and products.

Monica [59]3 years ago
3 0
The balanced reaction that describes the decomposition of methane to produce C2H2 and hydrogen is expressed <span>2ch4(g) = c2h2(g) + 3h2(g)  In the equilibrium, there are 4 moles of gas products produced from 2 moles of gas reactant. Hence, an increase in volume favors the forward reaction while increase in pressure favors the production of methane (backward). Equilibrium constant is expressed: Kp= (c2H2)^2(H2)^3/(Ch4)^2</span>
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A hypothetical wave has 4.6 J of energy. What is its hypothetical, approximate frequency?
Mariulka [41]

Answer:

6.94 × 10^33Hz

Explanation:

E = hf

Where;

E = Energy of wave (J)

h = Planck's constant (6.626 × 10^-34J/s)

f = frequency (Hz)

According to the information provided in this question, the hypothetical energy of the wave is 4.6J

Hence, using E = hf

4.6 = 6.626 × 10^-34 × f

f = 4.6 / 6.626 × 10^-34

f = 0.694 × 10^34

f = 6.94 × 10^33Hz

3 0
3 years ago
Given the following equation: 2NaClO3 --&gt; 2NaCl + 3O2
Dimas [21]
I’m not an expert and I haven’t taken chemistry in like a year but i believe you use stoichiometry to do this equation. It should look something like this.

8 0
3 years ago
What is the percent by mass of potassium in KFe(CN)?
vladimir1956 [14]

Answer:

Explanation:

1. Add the atomic mass of all the elements.

39+55.8+12+14= 120.8

2.Divide atomic mass of potassium by total atomic mass

39/120.8= .323

2. Multiply by 100

.323*100= %32.3 %32.3

8 0
4 years ago
The equilibrium constant Kc for the reaction below is 0.00584 at a certain temperature. Br2(g) ⇌ 2Br(g) If the initial concentra
Vinil7 [7]

Answer:

Explanation:

Given that:

The chemical equation for the reaction is:

             Br2(g)    ⇌  2Br(g)

Initially  0.0345M  0.0416M

Q_C = \dfrac{[Br]^2}{[Br_2]} = \dfrac{(0.0416)^2}{(0.0345)}= 0.05016

Q_C =0.05016 >>> K_c(0.00584)

Thus, the given reaction will proceed in the  backward direction

 The I.C.E table is as follows:

                       Br2(g)    ⇌  2Br(g)

I               0.0345                 0.0416

C                 +x                        -2x

E             (0.0345+x)            (0.0416 -2x)

K_c = \dfrac{[Br]^2}{[Br_2]} = \dfrac{(0.0416-2x)^2}{(0.0345+x)} = 0.00584

= 0.00173056 - 0.0832x - 0.0832x + 4x² = 0.00584 (0.0345 +x)

= 0.00173056 - 0.166x + 4x² = 2.0148× 10⁻⁴ + 0.00584x

= 0.00173056 - 2.0148× 10⁻⁴ - 0.166x - 0.00584x + 4x²

= 0.00152908  - 0.17184x + 4x²

Solving by using Quadratic formula

x = 0.03038 or 0.0126

For x = 0.03038

At equilibrium

[Br₂] = (0.0345 + 0.03038) = 0.06488 M

[Br] =  (0.0416 -2(0.03038)) = - 0.01916 M

Since we have a negative value for [Br], we discard the value for x

For x = 0.0126

At equilibrium

[Br₂] = (0.0345 + 0.0126) = 0.0471 M

[Br] =  (0.0416 -2(0.0126)) = 0.0164 M

4 0
3 years ago
In a particular breed of cattle, a black coat is dominant over a red coat. If a cow with a red coat is crossed with a black bull
larisa86 [58]
C.75%. Because the B is dominant 
3 0
3 years ago
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