Ask question

Ask question

All categories

3 years ago

10

Pls help and thank u need asap!

1 answer:

aleksandr82 [10.1K]3 years ago

5 0

Answer:

ill help if u help me?its 4am

You might be interested in

In Millikan's oil drop experiment an oil drop is at rest between two large plates separated by 1.3 cm when the potential differe

sweet-ann [11.9K]

Answer:

Mass of the oil drop, $m=3.01\times 10^{-15}\ kg$

Explanation:

Potential difference between the plates, V = 400 V

Separation between plates, d = 1.3 cm = 0.013 m

If the charge carried by the oil drop is that of six electrons, we need to find the mass of the oil drop. It can be calculated by equation electric force and the gravitational force as :

$qE=mg$

$m=\dfrac{qE}{g}$

$q=6e$ , e is the charge on electron

E is the electric field, $E=\dfrac{V}{d}=\dfrac{400}{0.013}=30769.23\ V/m$

$m=\dfrac{6\times 1.6\times 10^{-19}\times 30769.23}{9.8}$

$m=3.01\times 10^{-15}\ kg$

So, the mass of the oil drop is $3.01\times 10^{-15}\ kg$ . Hence, this is the required solution.

5 0

3 years ago

The volume of a gas can be converted to moles by

BaLLatris [955]

B. Because I say so

6 0

3 years ago

Hans Eysenck makes a connection between __________ and __________in explaining personality development. A. genetic factors . . .

tekilochka [14]

The answer is A, genetic factors...conditioning. I just took the test. Good luck!!

6 0

4 years ago

Read 2 more answers

Two masses are joined by a mass less string. A 33-N force applied vertically to the upper mass gives the system a constant upwar

lisov135 [29]

Lower mass: 1.20 kg, upper mass: 1.28 kg

Explanation:

In order to solve the problem, we consider the forces acting on the upper mass only first.

The upper mass is acted upon three forces:

The applied force $F_a=33 N$ , upward
The weight of the mass itself, $m_u g$ , where $m_u$ is the upper mass and $g=9.8 m/s^2$ is the acceleration of gravity, downward
The tension in the string, $T=16 N$ , downward

Therefore, the equation of the forces for the upper mass is:

$F_a - m_u g - T = m_u a$

where

$a=3.5 m/s^2$ is the acceleration (upward)

Solving for $m_u$ ,

$m_u = \frac{F_a-T}{a+g}=\frac{33-16}{3.5+9.8}=1.28 kg$

Now we can find the lower mass by considering the forces acting on it:

The tension in the string, T = 16 N, upward
The weight of the mass itself, $m_L g$ , where $m_L$ is the lower mass, downward

So the equation of the forces is

$T-m_L g = m_L a$

And solving for the mass,

$m_L = \frac{T}{a+g}=\frac{16}{3.5+9.8}=1.20 kg$

Learn more about acceleration and forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

7 0

3 years ago

Gold-leaf electroscope uses

Kruka [31]

-identifies an electric charge
-it can identify its polarity (positive or negative) if you compare it to a charge that you already know
-can identify the magnitude of a charge (how big of a charge it is)

7 0

4 years ago