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Rus_ich [418]
3 years ago
10

Comppare and contrast sexual reproucton and asexual repructon

Chemistry
1 answer:
JulsSmile [24]3 years ago
7 0

Answer:

Asexual reproduction involves only 1 parent. The daughter cells / offspring are the exact clones of the parent. There’s no variety. The end products are only 2 daughter cells. Sexual reproduction involves 2 parents (a mate). The offspring consists of a mixture of genes from both parents. There’s more variety to the offspring. 4 daughter cells are produced in sexual reproduction. Both undergo cell division. Asexual reproduction = mitosis Sexual reproduction = meiosis. Sexual reproduction produces the gametes, asexual produces body cells

Explanation:

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For the following reaction, 35.4 grams of zinc oxide are allowed to react with 6.96 grams of water . zinc oxide(s) + water(l) --
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Answer:

m_{Zn(OH)_2}=38.4g

Explanation:

Hello!

In this case, for the undergoing chemical reaction:

ZnO(s)+H_2O(l)\rightarrow Zn(OH)_2

We evaluate the yielded moles of zinc hydroxide by each reactant as shown below:

n_{Zn(OH)_2}^{by ZnO}=35.4gZnO*\frac{1molZnO}{81.38gZnO}*\frac{1molZn(OH)_2}{1molZnO}  =0.435molZn(OH)_2\\\\n_{Zn(OH)_2}^{by H_2O}=6.96gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{1molZn(OH)_2}{1molH_2O}  =0.386molZn(OH)_2

In such a way, since the water yields a smaller amount of zinc hydroxide we conclude it is the limiting reactant so the maximum mass is computed below:

m_{Zn(OH)_2}=0.386molZn(OH)_2*\frac{99.424 gZn(OH)_2}{1molZn(OH)_2} \\\\m_{Zn(OH)_2}=38.4g

Because the water limits the yielded amount of zinc hydroxide.

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