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Mkey [24]
3 years ago
12

a compound has 15.39 g of gold for every 2.77 g of chlorine. simplified there is _____ g of gold for every 1 g of chlorine

Chemistry
1 answer:
iren [92.7K]3 years ago
5 0

Answer:

There is 5.56 g of gold for every 1 g of chlorine

Explanation:

The ratio is the relationship between two numbers, defined as the ratio of one number to the other. So, the ratio between two numbers a and b is the fraction \frac{a}{b}

You know that a compound has 15.39 g of gold for every 2.77 g of chlorine. This can be expressed by the ratio:

\frac{15.39 g  of gold}{2.77 g of chlorine}

The proportion is the equal relationship that exists between two reasons and is represented by:    \frac{a}{b}=\frac{c}{d}

This reads a is a b as c is a d.

To calculate the amount of gold per 1 g of chlorine, the following proportion is expressed:

\frac{15.39 g  of gold}{2.77 g of chlorine}=\frac{mass of gold}{1 g of chlorine}

Solving for the mass of gold gives:

mass of gold=1 g of chlorine*\frac{15.39 g  of gold}{2.77 g of chlorine}

mass of gold= 5.56 grams

So, <u><em>there is 5.56 g of gold for every 1 g of chlorine</em></u>

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1 pts
soldier1979 [14.2K]

Answer:

144 g

Explanation:

Use the mole ratio of 4 mol CO2 for every 9 mol O2 to convert from mol O2 to mol CO2. Then use the molar mass of CO2 to convert from mol of CO2 to grams of CO2.

7.34 mol O2 • (4 mol CO2 / 9 mol O2) • (44.01 g CO2 / 1 mol CO2) = 144 g CO2

5 0
3 years ago
Read 2 more answers
Which has a higher concentration of water molecules— 200 molecules of water, or a mixture of 300 molecules of water and 100 mole
Dovator [93]
<h3>Answer:</h3>

            200 molecules of water has the highest concentration.

<h3>Explanation:</h3>

                    In chemistry, Concentration is defined as the amount of substance divided by the total volume of the constituents making the mixture.

<u>Case 1:</u> 200 Molecules of Water:

                                                     In this case we are having system which is made up of 200 purely water molecules and there is no other substance present in the system. Hence, for ease we can write it as,

           Concentration  =  Molecules of Water ÷ Total Molecules of Mixture

           Concentration  =  200 ÷ 200

           Concentration  =  1

<u>Case 2:</u> 300 Molecules of Water and 100 Molecules of Food Coloring:

                                                     In this case we are having a mixture which is made up of 300 water molecules and 200 food coloring molecules. Hence, we can write it as,

           Concentration  =  Molecules of Water ÷ Total Molecules of Mixture

           Concentration  =  300 ÷ (300 + 200)

           Concentration  =  300 ÷ 500

           Concentration  =  0.6

Therefore, it is proved that the concentration of pure 200 molecules of water is greater.

7 0
4 years ago
The maximum oxygen uptake is known as the __________.
andrezito [222]
The maximum oxygen uptake is known as the VO2 max.
4 0
3 years ago
Read 2 more answers
Cyclopropane, a substance used with oxygen as a general anesthetic, contains only two elements, carbon and hydrogen. When 1.00 g
ELEN [110]

Answer:

CH₂

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 1 g

Mass of CO₂ = 3.14 g

Mass of H₂O = 1.29 g

Empirical formula =?

Next, we shall determine the mass of Carbon and hydrogen present in the compound. This can be obtained as follow:

For Carbon, C:

Mass of CO₂ = 3.14 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Molar mass of C = 12 g/mol

Mass of C =?

Mass of C = molar mass of C/ Molar mass of CO₂ × Mass of CO₂

Mass of C = 12/44 × 3.14

Mass of C = 0.86 g

For hydrogen, H:

Mass of C = 0.86 g

Mass of compound = 1 g

Mass of H =?

Mass of H = (Mass of compound) – (mass of C)

Mass of H = 1 – 0.86

Mass of H = 0.14 g

Finally, we shall determine the empirical formula of the cyclopropane. This can be obtained as follow:

Mass of C = 0.86 g

Mass of H = 0.14 g

Divide by their molar mass

C = 0.86 / 12 = 0.07

H = 0.14 / 1 = 0.14

Divide by the smallest

C = 0.07 / 0.07 = 1

H = 0.14 / 0.07 = 2

Thus, the empirical formula of cyclopropane is CH₂

8 0
3 years ago
Name a common greenhouse gas containing ony hydrogen and oxygen
ruslelena [56]
<span>H2O, or water, in the form of water vapor, is a very strong greenhouse gas. Water vapor is part of a feedback loop where as the temperature increases, so does the water vapor, basically creating its own system where more water vapor is constantly being applied as a greenhouse gas to the atmosphere by its own evaporation into the atmosphere.</span>
7 0
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