Answer:
Current, I = 0.000109 Amps
Explanation:
Given the following data;
Voltage = 6V
Resistance = 55,000 Ohms
To find the current flowing through the circuit;
Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
Where;
V represents voltage measured in voltage.
I represents current measured in amperes.
R represents resistance measured in ohms.
Making current the subject of formula, we have;
Substituting into the formula, we have;
Current, I = 0.000109 Amps
I think the correct answer is C
Answer:
![N_{electrons}=Q_{transfered}/q_{electron}=5.94*10^{18}electrons](https://tex.z-dn.net/?f=N_%7Belectrons%7D%3DQ_%7Btransfered%7D%2Fq_%7Belectron%7D%3D5.94%2A10%5E%7B18%7Delectrons)
Explanation:
The total charge is distributed over the two objects:
![Q_{total}/2=(3.8*10^{-6}C+1.9C)/2=0.9500019C\\](https://tex.z-dn.net/?f=Q_%7Btotal%7D%2F2%3D%283.8%2A10%5E%7B-6%7DC%2B1.9C%29%2F2%3D0.9500019C%5C%5C)
The plate and the rod must have
. So the charge transferred from the plate to the rod is:
![Q_{transfered}=3.8*10^{-6}C-Q_{total}/2=3.8*10^{-6}C-0.9500019C=-0.9499981C\\](https://tex.z-dn.net/?f=Q_%7Btransfered%7D%3D3.8%2A10%5E%7B-6%7DC-Q_%7Btotal%7D%2F2%3D3.8%2A10%5E%7B-6%7DC-0.9500019C%3D-0.9499981C%5C%5C)
Number of electrons:
![N_{electrons}=Q_{transfered}/q_{electron}=-0.9499981C/(-1.6*10^{-19}C)=5.94*10^{18}electrons](https://tex.z-dn.net/?f=N_%7Belectrons%7D%3DQ_%7Btransfered%7D%2Fq_%7Belectron%7D%3D-0.9499981C%2F%28-1.6%2A10%5E%7B-19%7DC%29%3D5.94%2A10%5E%7B18%7Delectrons)
To solve this problem we will use the kinematic equations of angular motion, starting from the definition of angular velocity in terms of frequency, to verify the angular displacement and its respective derivative, let's start:
![\omega = 2\pi f](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%20f)
![\omega = 2\pi (2.5)](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%20%282.5%29)
![\omega = 5\pi rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%205%5Cpi%20rad%2Fs)
The angular displacement is given as the form:
In the equlibrium we have to
and in the given position we have to
![\theta(t) = \theta_0 cos(5\pi t)](https://tex.z-dn.net/?f=%5Ctheta%28t%29%20%3D%20%5Ctheta_0%20cos%285%5Cpi%20t%29)
Derived the expression we will have the equivalent to angular velocity
![\frac{d\theta}{dt} = 2.7rad/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5Ctheta%7D%7Bdt%7D%20%3D%202.7rad%2Fs)
Replacing,
![\theta_0(sin(5\pi t))5\pi = 2.7](https://tex.z-dn.net/?f=%5Ctheta_0%28sin%285%5Cpi%20t%29%295%5Cpi%20%3D%202.7)
Finally
![\theta_0 = \frac{2.7}{5\pi}rad = 9.848\°](https://tex.z-dn.net/?f=%5Ctheta_0%20%3D%20%5Cfrac%7B2.7%7D%7B5%5Cpi%7Drad%20%3D%209.848%5C%C2%B0)
Therefore the maximum angular displacement is 9.848°
Newton has 3 Laws specifically The Three Laws of Motion