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adelina 88 [10]

3 years ago

5

Reduce, reuse, recycle! Soft drinks come in aluminum cans that are readily recycled. Storage of empty cans is never a problem, s

ince aluminum cans are easily crushed because they are very A) conductive. B) magnetic. C) malleable. D) soluble.

2 answers:

ryzh [129]3 years ago

8 0

Malleable is correct

natita [175]3 years ago

6 0

They are C, Malleable.

I hope this helps! (:

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The barrel of a rifle has a length of 0.855 m. A bullet leaves the muzzle of a rifle with a speed of 553 m/s. What is the accele

Novay_Z [31]

Answer:

Acceleration of the bullet will be 1778835.6 $m/sec^2$

Explanation:

We have given length of the barrel refile s= 0.855 m

When the bullet leaves the muzzle its velocity is 553 m/sec

So final velocity v = 553 m/sec

Initial velocity will be 0 that is u = 0 m/sec

According to third equation of motion $v^2=u^2+2as$

$553^2=0^2+2\times a\times 0.855$

$a=178835.6m/sec^2$

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3 years ago

In football we see unbalanced forces. When 1 player exerts an unbalanced force on another player and causes a player to

zaharov [31]

Answer:

Fall

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3 years ago

A wire of 2kg is attached to the end of a vertical wire of length 2m and

snow_tiger [21]

Answer:

12732.4 N/mm^2

Explanation:

y = stress/strain

8 0

3 years ago

A portion of Nichrome wire of radius 2.50 mm is to be used in winding a heating coil. If the coil must draw a current of 9.25 A

Sedaia [141]

The resistance of the coil is 12. 97 Ω

<h3>How to determine the length</h3>

The formula for resistance is given as;

R = V/I

Note that resistance, R is measured in Ohms and represented with the symbol ( Ω)

Where;

V is the voltage = 120 V
I is the current = 9. 25 A

Substitute the values into the formula

R = 120/ 9. 25

R = 12. 97 Ω

The resistance, R is 12. 97 Ω

Hence, the resistance of the coil is 12. 97 Ω

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5 0

1 year ago

If a sound is 30 dB and its absolute pressure was 66 x 10-9 Pa, what must have been the reference pressure?

Ksenya-84 [330]

Given:

I = 30dB

P = 66 × $10^{-9}$ Pa

Solution:

Formula used:

I = $20\log_{10}(\frac{P}{P_{o}})$ (1)

where,

I = intensity of sound

P = absolute pressure

$P_{o}$ = reference pressure

Using Eqn (1), we get:

$30 = 20\log _{10}\frac{66\times 10^{-9}}{P^{o}}$

$P_{o}$ = $\frac{66\times 10^{-9}}{10^{1.5}}$

$P_{o}$ = 2.08 × $10^{-9}$ Pa

4 0

3 years ago