The answer is to your question is c
For a concave mirror, the radius of curvature is twice the focal length of the mirror:
where f, for a concave mirror, is taken to be positive.
Re-arranging the formula we get:
and since the radius of curvature of the mirror in the problem is 24 cm, the focal length is
Main Answer:
Given speed of spaceship v = 0.8c = 0.8 * 3 x 10^8 m/s
Speed of spaceship v = 2.4 x 10^8 m/s
Distance need to be travelled d = 4.3 light years
we know that 1 light year = 9.461 x 10^15 m
Distance need to be travelled d = 4.3 x 9.461 x 10^15
d = 40.6823 x 10^15 m
Time taken for the trip would elapse on a clock on board the spaceship
t = distance/ velocity
t = 40.6823 x 10^15 / 2.4 x 10^8
t = 16.95 x 10^7 sec
t = 4.71 x 10^4 hours
Explanation:
What is light year?
Light year is defined as the distance travelled by the light in one year. In a year, light travels through 300000 km per sec in the interstellar space.
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Answer:
τsolid = 0.15 N•m
τhoop = 0.30 N•m
Explanation:
θ = ½αt²
α = 2θ/t² = 2(14)/8.3² = 0.406445 rad/s²
Solid disk I = ½mr² = ½(4.2)0.42² = 0.37044 kg•m²
τ = Iα = 0.37044(0.406445) = 0.150563... N•m
Hoop disk I = mr² = (4.2)0.42² = 0.74088 kg•m²
τ = Iα = 0.74088(0.406445) = 0.301127... N•m
Answer:
gravitational force and outward pressure
Explanation:
The stars are very massive stellar objects, so they have a strong gravitational force, which drives the star to contract itself, but also in stars there are nuclear reactions such as fusion of hydrogen and other elements, that releases energy and creates a pressure from the center to the star exterior, an outward pressure that goes against the gravitational force. So when a star is stable these two forces exist in equilibrium or in balance, in which the star does not collapse by gravity or disintegrate by its outward pressure.
