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3 years ago

What is the weight of a 90kg man standing on the moon, where gmoon = 1.64 m/s2?

Chemistry

1 answer:

Doss [256]3 years ago

3 0

Answer:

The weigth of a 90kg man standing on the moon is 147.6 N (option C)

Explanation:

Weight is called the action exerted by the force of gravity on the body.

The mass (amount of matter that a body contains) of an object will always be the same, regardless of where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

The formula that allows you to calculate the weight of any body is:

W = m*g

where:

W = weight measured in N.
m = mass measured in kg.
g = acceleration of gravity measured in m/s². The acceleration of gravity g is the same for all objects that fall due to gravitational attraction, whatever their size or composition. For example, as an approximate value on Earth, g = 9.8 m/s².

In this case, the mass m has a value of 90 kg and the gravity g has a value of 1.64 m/s², which is the value of the acceleration of gravity of the moon. Then:

W=90 kg* 1.64 m/s²

W= 147.6 N

Finally, the weigth of a 90kg man standing on the moon is 147.6 N (option C)

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Given the reaction below, if 0.00345 g of carbon dioxide is used up, how many grams of water will be produced?

zimovet [89]

From the stoichiometry of the reaction, 1.4 * 10^-3 g is produced.

<h3>What mass of water is produced?</h3>

The equation of the reaction is written as; CO2 + 2LiOH → Li2CO3 + H2O. This can help us to apply the principle of stoichiometry here.

Thus;

Number of moles of CO2 = 0.00345 g/44 g/mol = 7.8 * 10^-5 moles

If 1 mole of CO2 produced 1 mole of water

7.8 * 10^-5 moles of CO2 produced 7.8 * 10^-5 moles of water

Mass of water produced = 7.8 * 10^-5 moles * 18 g/mol = 1.4 * 10^-3 g

Learn ore about stoichiometry:brainly.com/question/9743981

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3 0

2 years ago

Of the following solutions, which has the greatest buffering capacity?

Goshia [24]

Answer:

d. 0.121 M HC2H3O2 and 0.116 M NaC2H3O2

Explanation:

Hello,

In this case, since the pH variation is analyzed via the Henderson-Hasselbach equation:

$pH=pKa+log(\frac{[Base]}{[Acid]} )$

We can infer that the nearer to 1 the ratio of of the concentration of the base to the concentration of the acid the better the buffering capacity. In such a way, since the sodium acetate is acting as the base and the acetic acid as the acid, we have:

a. $\frac{[Base]}{[Acid]}=\frac{0.497M}{0.365M}=1.36$

b. $\frac{[Base]}{[Acid]}=\frac{0.217M}{0.521M}=0.417$

c. $\frac{[Base]}{[Acid]}=\frac{0.713M}{0.821M}=0.868$

d. $\frac{[Base]}{[Acid]}=\frac{0.116M}{0.121M}=0.959$

Therefore, the d. solution has the best buffering capacity.

Regards.

4 0

3 years ago

If ahahah ahahahajja hajajiaja hajajwija hahaha jakakwkka ahsiwkwkkw

deff fn [24]

Answer:

Explanation:

no explanation cos no questions

8 0

3 years ago

Read 2 more answers

Ca(OH)₂(s) precipitates when a 1.0 g sample of CaC₂(s) is added to 1.0 L of distilled water at room temperature. If a 0.064 g sa

Alex

Answer:

D) Ca(OH)₂ will not precipitate because Q < Ksp

Explanation:

This is a question in which we will employ the reaction quotient Q to determine whether a precipitate will form.

Here we have first a chemical reaction in which Ca(OH)₂ is produced:

CaC₂(s) + H₂O ⇒ Ca(OH)₂ + C₂H₂

Ca(OH)₂ is slightly soluble, and depending on its concentration it may precipitate out of solution.

The solubility product constant for Ca(OH)₂ is:

Ca(OH)₂(s) ⇆ Ca²⁺(aq) + 2OH⁻(aq)

Ksp = [Ca²⁺][OH⁻]²

and the reaction quotient Q:

Q = [Ca²⁺][OH⁻]²

So by comparing Q with Ksp we will be able to determine if a precipitate will form.

From the stoichiometry of the reaction we know the number of moles of hydroxide produced, and since the volume is 1 L the molarity will also be known.

mol Ca(OH)₂ = mol CaC₂( reacted = 0.064 g / 64 g/mol = 0.001 mol Ca(OH)₂

Thus the concentration of ions will be:

[Ca²⁺ ] = 0.001 mol / L 0.001 M

[OH⁻] = 2 x 0.001 M = 0.002 M ( From the coefficient 2 in the equilibrium)

Now we can calculate the reaction quotient.

Q= [Ca²⁺][OH⁻]² = 0.001 x (0.002)² = 4.0 x 10⁻⁹

Q < Ksp since 4.0 x 10⁻⁹ < 8.0 x 10⁻⁸

Therefore no precipitate will form.

The answer that matches is (D)

6 0

3 years ago

PLEASE EXPLAIN I KNOW THE ANSWER I NEED AN EXPLAINATION

BaLLatris [955]

From the graph shown, Y2 = N2, X2 = O2, Z2 = H2.

When atoms of elements are at a large distance from each other, the potential energy of the system is high. However, as the atoms approach each other, the potential energy of the system decreases steadily. The closer the atoms come to each other, the lower the potential energy. This implies that potential energy is proportional to bond length.

Since N2 has a shorter bond length and higher energy, Y2 must be N2. The bond energy of hydrogen is small hence H2 must be X2. The bond energy of a double bond is intermediate between that of a single and triple bond hence Z2 must be O2.

Learn more: brainly.com/question/24857760

6 0

2 years ago